Given the radii of two wires is of the ratio 2:1.
Using the formula as per Hooke's law,
i) When both the wires are under the same stress, strain produced will be the same.
ii) When both the wires are loaded by the same weight, then
Given,
Wire is increased of it's length, i.e., strain = 10-3
Stress = 108N/m2
A wire loaded by weight of density 7800 kg/m3 is stretched to length of 1m. On immersing the weight in liquid of density 1300kg/m3, the length shortens by 6mm. Find the original length of the wire.
Given,
Density of the load, ρ = 7800 kg/m3
Length of the wire, l = 1 m
Density of liquid, = 1300 kg/m3
Let, V be the volume of weight suspended from the wire.
Therefore, tension in the wire when load is in the air is equal to,