Given,
Length of one end of wire, L = 1m
Angular velocity,=12 rad/s
Mass of the load, M=2kg
Therefore tension in the string is,
Increase in the length of the wire = (5.53 - 1) = 4.53 m
Given,
Weight of the load = 200 N
Elongation caused in the wire is given by,
To find - Elastic potential energy stored in the wire = ?
Therefore, energy stored in the wire is given by,
The situation is shown in figure.
From right angled
The different forces acting on mass are:
(i) Weight mg in vertically downward direction. (ii) Tension T in the string along AS. Resolve the components of T as shown in figure. The component 7cosθ balances the weight mg of the mass and component 7sinθ provides the necessary centripetal force to whirl the mass.
Length of the wire, l = 4m
Radius of the wire, r = 4 mm = 0.004 m
Force on the wire, F = 80
Strain = 0.01% = 0.0001
Now, using the formula of stress,
=
Young's modulus of the wire is given by,
Y =