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Alternating Current

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Physics Part I

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Physics

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The peak voltage of an ac supply is 300 V. What is the rms voltage?


Given,

Peak volatge, E0 = 300 VRms value of current,  Irms = 10 A 

Now,
Using the relation,

                     Erms = E02 

                           = 3002 = 3001.414 = 212.13 V

1065 Views

A 100 Ω resistor is connected to a 220 V, 50 Hz ac supply.
What is the rms value of current in the circuit?


Given, 

Resistance, R = 100 ΩVoltage applied, V = 220 V Frequency of the AC supply, f = 50 Hz 

 ω = 2π f = 2 ×3.14 × 50 = 314 

 Using the relation
                    Ieff = VeffR
Putting values,
                       Ieff =220100 = 2.2 A

1559 Views

A 100 Ω resistor is connected to a 220 V, 50 Hz ac supply.
What is the net power consumed over a full cycle?

Given, 

Resistance, R = 100 ΩPotential applied, V = 220 ( effective voltage Veff)frequency, f = 50 Hz 

Since, ω = 2π f = 2 ×3.14 × 50 = 314 
Therefore,
Power consumed = Current x Voltage
                        = Ieff × Veff 

                        = 2.2 x 200
                        = 484 watt.


1061 Views

The rms value of current in an ac circuit is 10 A. What is the peak current?


Given, 

Peak voltage, E0 = 300 VRms value of current, Irms = 10 A 

Hence, using the formula,

              Irms = I02
         
                 I0 = 2  Irms

                    = 2 × 10 = 14.1 A. 
which is the required value of peak current. 

1031 Views

44 mH inductor is connected to 220 V, 50 Hz ac supply. Determine the rms value of the current in the circuit.


Given,
Inductance, L = 44 mH = 44 × 10-3H

Frequency of the Ac supply, f = 50 HzRms value of voltage, Erms = 220 V 

Inductive reactance is given by, XL = L.ω                                                             = L. 2πf                                                            = 44 × 10-3 × 2 × 3.14 × 50
Now,
                    Irms = ErmsXL         = 22044 ×10-3×2×3.14×50
                         = 15.9 A. 

920 Views