Advertisement

When a metallic surface is illuminated with radiation of wavelength straight lambda, the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2 straight lambda, the stopping potential is V/4. The threshold wavelength for the metallic surface is,

  • 5 straight lambda
  • 5 over 2 lambda
  • 3straight lambda

  • 3straight lambda


C.

3straight lambda

When a metallic surface is illuminated with radiation of wavelength , the stopping potential is V.

Photoelectric equation can be written as,

        ... (i)
Now, when the same surface is illuminated with radiation of wavelength 2, the stopping potential is V/4. So, photoelectric equation can be written as,


From equations (i) and (ii), we get

3353 Views

Advertisement

A black body is at a temperature of 5760 K. The energy of radiation emitted by the body at wavelength 250 nm is U1, at wavelength 500 nm is U2 and that at 1000 nm is U3. Wien's constant, b = 2.88 x 106 nmK. Which of the following is correct?

  • U3 = 0

  • U1 > U2

  • U2 > U1

  • U2 > U1


C.

U2 > U1

Given, temperature, T1 = 5760 K

Given that energy of radiation emitted by the body at wavelength 250 nm in U1, at wavelength 500 nm is U2 and that at 1000 nm is U3.

Now, according to Wein's law, we get


where, b = Wien's constant = 2.88 x 106 nmK




 is the wavelength corresponding to maximum energy, so U2 > U1.

2811 Views

A radiation of energy 'E' falls normally on a perfectly reflecting surface. The momentum transferred to the surface is 
(c = velocity of light)

  • straight E over straight c
  • fraction numerator 2 straight E over denominator straight c end fraction
  • fraction numerator 2 straight E over denominator straight c squared end fraction
  • fraction numerator 2 straight E over denominator straight c squared end fraction

B.

fraction numerator 2 straight E over denominator straight c end fraction

The radiation energy is given by 

1114 Views

An electron of mass m and a photon have the same energy E. The ratio of de-Broglie wavelength associated with them is,

  • open parentheses fraction numerator straight E over denominator 2 straight m end fraction close parentheses to the power of begin inline style bevelled 1 half end style end exponent
  • straight c space left parenthesis 2 mE right parenthesis to the power of begin inline style bevelled 1 half end style end exponent
  • 1 over straight c open parentheses fraction numerator 2 m over denominator E end fraction close parentheses to the power of begin inline style bevelled 1 half end style end exponent
  • 1 over straight c open parentheses fraction numerator 2 m over denominator E end fraction close parentheses to the power of begin inline style bevelled 1 half end style end exponent

D.

1 over straight c open parentheses fraction numerator 2 m over denominator E end fraction close parentheses to the power of begin inline style bevelled 1 half end style end exponent

Given that electron has a mass m.

De-Broglie wavelength for an electron will be given as,



where,

h is the Planck's constant, and
p is the linear momentum of electron

Kinetic energy of electron is given by, E = 


From equation (i) and (ii), we have


Energy of a photon can be given as,




Hence,  is the de-Broglie wavelength of photon.

Now, dividing equation (iii) by (iv), we get

5203 Views

A caesium photocell, with a steady potential difference of 60 V across it, is illuminated by a bright point source of light 50 cm away. When the same light is placed 1 cm away, the photoelectrons emitted from the cell

  • are half as numerous

  • are one quarter as numerous

  • each carry one quarter of their previous energy

  • each carry one quarter of their


B.

are one quarter as numerous

Number of photo electrons emitted will be 1/4th as previous.


Advertisement