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For the reaction
: 2A + B + C → A
2B
the rate = k[A] [B]
2 with k = 2.0 x 10–6 mol–2L2s–1.
Calculate the initial rate of the reaction when [A] = 0.1 mol L-1, [B] = 0.2 mol L-1and [C] = 0.8 M. Calculate the rate of reaction after [A] is reduced to 0.06 mol L
–1.

In the reaction
2A + B + C → A2B + C,
there is no change in C, therefore its conc. does not affect the rate of the reaction.
Initial rate = k[A] [B]2
But [A] = 0.1 M,
[B] = 0.2 M
and k = 2 x 10–6 M–2 s–1

Therefore initial rate

Rate= [k] x [A] x [B]2

= 2 x 10–6 M–2 s–1 x (0.1 M) (0.2 mol M)2 = 8 x 10–9 ms–1

From the equation:

2A + B + C → A2B + C,

it is clear that when 2 moles of A are used then 1 mol of B is used in the same time. Therefore, when A has been reduced to 0.06 M (due to its 0.04 M has been reacted to 0.02 of B). Thus,

Conc. of A left = [A] = 0.06 M
Conc. of B left = [B] = [0.02 M – 0.02 M]
= 0.018 M

Rate = k[A] [B]2
= 2 x 10–6 M2 S–1 x (0.06 M) (0.18 M)
= 3.89 x 10–9 Ms–1.

263 Views

From the rate expression for the following reactions, determine their order of reaction and the dimensions of the rate constants
(i) 3NO(g) → N2O (g) Rate = k[NO]2
(ii) H2O2 (aq) + 3I (aq) + 2H+ → 2H2O (l) + I-Rate = k[H2O2][I-]
(iii) CH3CHO (g) → CH4 (g) + CO(g) Rate = k [CH3CHO]3/2
(iv) C2H5Cl (g) → C2H4 (g) + HCl (g) Rate = k [C2H5Cl]


(a) Rate = k[NO]2
Order w.r.t. NO(g) = 2
Overall order of reaction = 2
Rate constant, 
                k = Rate[NO]2 = conc./time(conc.)2
     1conc. time= 1mol L-1s                      = L mol-1 s-1
The dimensions of the rate constant, k are L mol–1 s–1

(b) Rate = k[H2O2] [I]
Order w.r.t., H2O2 = 1
Order w.r.t., I= 1
Order w.r.t., I+ = 0
Overall order of reaction = 1 + 1 = 2
Rate constant,
k=Rate[H2O2] [I-] =conc./timeconc.2
  = 1conc.time = 1mol L-1s= L mol-1 s-1
The dimensions of rate constant, k are L mol–1 s–1.

(c) Rate = k[CH3CHO]3/2
Order w.r.t., CH3CHO = 3/2 = 1.5
Overall order of reaction = 1.5
Rate constant,
k = Rate[CH3CHO]3/2 = conc./timeconc.3/2   = 1conc.1/2×s = 1(mol L-1)1/2s  = L1/2 mol-1/2 s-1   
The dimensions of rate constant, k are L1/2 mol–1/2 s–1.

(d) Rate  = kCHCl3 [Cl2]1/2
Order w.r.t. [CHCl3] = 1
Order w.r.t. Cl2(g) = 12=  0.5
Overall order of reaction  = 1+0.5 = 1.5
Rate constant,
k= Conc./timeCHCl3 Cl21/2 =conc./timeconc.3/2    = 1(mol L-1)1/2 x s= L1/2 mol-1/2 s-1
The dimensions of rate constant, k are L1/2 mol–1/2 s–1.

205 Views

List the factors on which the rate of a chemical reaction depends.

The various factors which affect the rate of chemical reactions are:
(i) Concentration of reactants
(ii) Temperature of reaction
(iii) Presence of catalyst
(iv) Nature of reactants
(v) Surface area
(vi) Exposure to radiations.

238 Views

The decomposition of NH3 on platinum surface is a zero order reaction. What are the rates of production of N2 and H2 if k = 2.5 x 10–4 mol–1 L s–1 ?

Rate of reaction can be 

dxdt=-12d(NH3)dt=d(N2)dt=13dH2dt=k.

k is rate constant and reaction is of zero order. Therefore, rate of reaction


dxdt=dH2dt=2.5×10-4 Ms-1

Rate of production of H2, is given by

dH2dt=3dH2dt             = 3×2.5×10-4Ms-1 = 7.5×10-4 Ms-1.
883 Views

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The decomposition of NH3 on platinum surface is zero order. What are the rates of production of N2 and H2 if k = 2.5 x 10–4 mol–1 Ls–1?


The decomposition of NH3 on plantinum surface is given as,

2NH3  N2+3H2Rate of reaction,              dxdt=-12d(NH3)dt                      = dN2dt = 13dH2dt=k.

k is rate constant and reaction is of zero order.
      Therefore, rate of reaction,


    dxdt=dH2dt=2.5×10-4Ms-1

Rate of production of H2, is given by
      

dH2dt=3dH2dt              = 3×2.5×10-4Ms-1 = 7.5×10-4 Ms-1.
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