According to the collision theory of chemical reactions
A chemical reaction occurs with every molecular collision
Rate is directly proportional to the number of collisions per second
Reactions in the gas phase are always of zero order
Reaction rates are of the order of molecuar speeds
B.
Rate is directly proportional to the number of collisions per second
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For the reaction is equal to
B.
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In which of the following cases, does the reaction go farthest to completion
k = 102
k = 10–2
k = 10
k = 1
A.
k = 102
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For the reaction A B, the rate of reaction becomes twenty seven times when the concentration of A is increased three times. What is the order of the reaction?
r= k[A]n =Kan When concentration is increased three time [ A] =3a therefore,
Order = 3.
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What will be the order of reaction if doubling of the concentration of a reactant increases the rate by a factor of 4 and trebling the concentration of the reactant by factor of 9?