Conductivity of 0.00241 M acetic acid is 7.896 x 10–5 S cm–1. Calculate its molar conductivity, if Λ° for acetic acid is 390.5 S cm2 mol–1, what is its dissociation constant?
We have given that
Concentration = 0.00241M
Conductivity =0.00241S Cm-1
thus by using the formula
we get
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