The resistance of a conductivity cell containing 0.01 M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001 M KCl solution at 298 K. is 1.46 x 10–6 s cm–1.
We ave given that
R = 1500 Ω K = 1.46 x 10–4 Ω–1 cm–1
Cell constant = K x R
= 1.46 x 10–4 x 1500 = 0.219
How would you determine the standard electrode potential of the system Mg2+/Mg?
Use standard hydrogen electrode as anode and Mg2+ | Mg as a cathode we can measure the standard electrodepotential of systemMg2+ | Mg. Standard hydrogen electrode, represented by Pt(s), H2(g) (1 atm) | H+ (aq) and dip the electrode of Magnesium wire in a 1M MgSO4 solution .The standard hydrogen electrode is always zero.