ï»¿ The conductivity of 0.1 M KCl solution at 298 K is 0.0129 s cm–1. The resistance of this solution in a conductivity cell is found to be 58 ohms. What is the cell constant of the cell? The 0.1 M AgNO3 solution at 298 K in the same conductivity cell offered a resistance of 60.5 ohms. What is the conductivity of 0.1 M AgNO3 solution? from Chemistry Electrochemistry Class 12 Nagaland Board

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The conductivity of 0.1 M KCl solution at 298 K is 0.0129 s cm–1. The resistance of this solution in a conductivity cell is found to be 58 ohms. What is the cell constant of the cell? The 0.1 M AgNO3 solution at 298 K in the same conductivity cell offered a resistance of 60.5 ohms. What is the conductivity of 0.1 M AgNO3 solution?

KKCl = 0.0129 s cm–1
RKCl = 58 Ω
cell constant= k x R
cell constant= 0.0129 x 58
Cell constant = 0.7482 cm–1
As AgNO3 is also in the same conductivity cell, the cell constant remains same. Therefore,
Conductivity of

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Consult the table of standard electrode potentials and suggest three substance that can oxidize ferrous ions under suitable conditions.

Answer:

oxidation of ferrous ion means :

Fe2+--> Fe3+ +e-
Any substance which standard electrode potential is more than that of Fe+3 /F+2 can oxidise ferrous ions.
(refer to the table given in book)

The EMF of the substance whose reduction potentials greater than 0.77V will oxidised ferrous ion.
for example Br2, Cl2,and F2 .

879 Views

How would you determine the standard electrode potential of the system Mg2+/Mg?

Answer:

Use standard hydrogen electrode as anode and Mg2+ | Mg as a cathode we can measure the standard electrodepotential of systemMg2+ | Mg. Standard hydrogen electrode, represented by Pt(s), H2(g) (1 atm) | H+ (aq) and dip the electrode of Magnesium wire in a 1M MgSO4 solution .The standard hydrogen electrode is always zero.
Use formula
Eocell = Eo right  – Eoleft
The standard hydrogen electrode is always zero.
So that the value of
Eoleft =0
Hence
Eocell = Eo Mg|Mg2+
Or
Eo Mg|Mg2+= Eocell
2203 Views

Can you store copper sulphate solutions in a Zinc pot?

Answer:

No. Because zinc is more reactive than copper and thus holes will be developed in zinc pot.

Cu2+(aq) + Zn(s) → Zn2+ (aq) + Cu(s)
1384 Views

Calculate the emf of the cell in which the following reaction takes place:
Ni(s) + 2Ag+ (0.002 M) $\to$ Ni2+ (0.160 M) + 2Ag(s)
Given that

Answer:

$\mathrm{Ni}\left(\mathrm{s}\right)+2{\mathrm{Ag}}^{+}\left(\mathrm{aq}\right)\to {\mathrm{Ni}}^{2+}\left(\mathrm{aq}\right)+2\mathrm{As}\left(\mathrm{s}\right)$

or

The equation is also written as

or

= 1.05 V – 0.0295 x log 80

= 1.05 V – 0.0295 x 1.9031

= 1.05 V – 0.056 = 0.99 V.

1585 Views

Calculate the potential of hydrogen electrode in contact with a solution whose pH is 10.

Answer:

For hydrogen electrode, ,
given that      pH = 10
use formula [H+] = 10–pH
so that  [H+] = 10−10 M
Electrode reaction will
H+  + e –  →1/2 H2
Use the formula

1279 Views