The electrode potentials of four elements A, B, C and D are 1.36 V - 0.32 V, 0.0 V and – 1.26 V respectively. Arrange these elements in the decreasing order of reactivity.

Answer:

The reactivity decreases as the electrode potential increases, the correct order of decreasing order of reactivity is D > B > C > A .
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Given the two half cell reaction:
Anode: Cu(s) → Cu2+ (aq) + 2e
Cathode: Ag+ (aq) + e → Ag(s)
Write the galvanic cell for the net reaction.

Answer:

The net cell reaction is
Cu(s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag(s)
and the galvanic cell is
Cu(s) |Cu2+ (aq) || Ag+ (aq) | Ag(s)

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What is it that ‘Al’ metal cannot be obtained by electrolysis of an aqueous solution of a salt of aluminium?

Answer:

The reduction potential of aluminium is lower than that of water this means that it has lesser tendency to get reduced than water .
since water has higher reduction potential thus aluminium on electrolysis of an aqueous solution of a salt of aluminium.

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What happens to free energy during operation of a cell?


Answer:

It goes on decreasing.
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How many Faradays of electricity are required to liberate 2 moles of hydrogen gas in electrolysis of aq. solution?

Answer:

4H
+ + 4e– → 2H2(g).
4 Faraday of electricity is required to liberate 2 moles of hydrogen gas.
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