What is the effect of temperature on solubility of salt in water?

Answer:

Temperature does effect the solubility of any solid solute in a solution,like in the case of salt in water.the effect of temperature depends on the nature of reaction.if the reaction is an endothermic reaction,then the increase in temperature has a positive effect and the solubility increases.if it is an exothermic process,then the increase in the temperature would not favour the solubity of the solute.

For Salt + Water Solution ΔH = + ve or for endothermic dissolution of salt, the solubility increases with temperature. Where as for exothermic dissolution. Salt + Water → Solution. ΔH = – ve > the solubility decreases with temperature.
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What happens to vapour pressure of solution if table sugar or table salt is added to water?


Addition of a non-volatile solute always lowers the vapour pressure of solvent.
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Why do gases nearly always tend to be less soluble in liquids as the temperature is raised?

Answer:

Gas  in liquid it generate a small quantity of heat so we can say that dissolution of gas in a liquid is a exothermic reaction.
Gas + liquid  < --- >  solution  + heat
According to Le chatelier's principle  when we increase the temperature in a exothermic reaction , the reaction will move to back ward direction that means solution will dissociate and will give gas .Hence with the rise of temperature gas will less soluble.
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Define Raoult’s law? 

Answer:

Raoult’s law states that "for a solution of volatile liquids the partial vapour pressure of each component in the solution is directly proportional to its mole fraction.

        p1 ∝ x1
and  p1 = p1° x1
 where p1° is  vapour pressure in the pure state

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How is osmotic pressure related to the concentration (or number of moles) of a solute in solution?

osmotic pressure is proportional to the molarity, C of the solution at a given temperature T. Thus:
Π = C R T 
Here Π is the osmotic pressure and R is the
gas constant.
Π = (n2 /V) R T 
Here V is volume of a solution in litres containing n2 moles of solute.
If w2 grams of solute, of molar mass, M2 is present in the solution, then n2 = w2 / M2 and we can write

πV = w2RTM2


Thus, knowing the quantities w2, T, Π and V we can calculate the
molar mass of the solute.

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