AS both the solution are isotonic they should have same concentrationin mole/litre
for sucrose solution concentration =4g/100cm3
molar mass of sucrose C 12H22O11 = 342
therefore we get =40/342 moles/litre
For unknown substance Let N be the molecular mass then concentration = 3g/100cm3
= 30/N moles/Litre
comparing the both equation
30/N = 40/342
N=(30 x 342)/40
Molecular mass of oragnic compound
Molarity (M) is defined as number of moles of solute dissolved in one litre (or one cubic decimetre) of solution.
(a) Mol. mass of
Volume of solution = 4.3 L
(b) Number of moles present in 1000 ml of 0.5M H2SO4= 0.5 mol
therefore number of moles present in 30ml of 0.5M H2SO4=mol =0.015mol
therefore molarity =0.015/0.5L
thus molarity is 0.03M
Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.
Let the total mass of the solution be 100g and mass of benzene be 30 g
therefore mass of tetrachloride= (100-30)g = 70g
Molar mass of benzene,
Calculate (a) molality (b) molarity and (c) mole fraction of KI if the density of 20% (mass/mass) aqueous KI is 1.202 g mL-1.
Molality (m) is defined as the number of moles of the solute per kilogram (kg) of the solvent and is expressed as: