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The Solid State

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Chemistry I

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Chemistry

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Class 10 Class 12
Copper crystallizes into a fcc lattice with edge length 3.61 x 10–8 cm. Show that the calculated density is in agreement with its measured value of 8.92 g cm–3.

We have given that

Length of edge, a = 3.61x10–8 cm
Atomic mass of cupper, M = 63.55 g/mol
Avogadro constant, NA = 6.022x1023 per mol
Number of atoms in unit cell of FCC, Z= 4

Use formula of density,

straight p equals fraction numerator ZM over denominator straight a cubed straight N subscript straight A end fraction

Putting space the space given space value space in space above space equation

straight p space equals fraction numerator 4 space straight x space 63.55 over denominator left parenthesis 3.61 space straight x 10 to the power of negative 8 end exponent right parenthesis cubed space left parenthesis 6.022 space straight x 10 to the power of 23 right parenthesis end fraction straight g over Cm cubed

straight p equals space fraction numerator 254.2 over denominator left parenthesis 47.04 space space straight x 10 to the power of negative 24 end exponent right parenthesis space left parenthesis 6.022 space straight x 10 to the power of 23 right parenthesis end fraction

straight p equals space fraction numerator 254.2 over denominator 28.318 end fraction straight g over cm cubed

straight p equals 8.92 space straight g divided by cm cubed

 




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