﻿ An atom has fcc crystal whose density is 10 gm–3 and cell edge is 100 pm. How many atoms are present in its 100 g? from Chemistry The Solid State Class 12 Nagaland Board

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An atom has fcc crystal whose density is 10 gm–3 and cell edge is 100 pm. How many atoms are present in its 100 g?

Solution:
We have given that
Density = 10 gm-3
Mass = 100g
edge of unit cell ,a= 4 since it is a Fcc crystal

we have to find total number of atom, So by following relation we can get the result,

Total No. of atoms = $\frac{\mathrm{Z}×\mathrm{M}}{{\mathrm{a}}^{3}.\mathrm{d}}$

Therefore, number of atoms

thus the number of atoms is 4 x 1031

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