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    The Solid State
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    What is possible formula of a compound which is made of two elements P and Q and forms fcc structure. Atoms P occupy corner positions and Q occupy face positions of cube?
    In a fcc unit cell, there are 8 corners and 6 faces. Eight corners contribute 8 x 1/8 = 1 atom
    six faces contribute 6 x 1/2 = 3 atoms.
    So the formula of the compound is PQ    3.
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    What is the general structure of ionic solids?
    In ionic solids, generally anions form close-packed structure and cations occupy interstitial sites. example NaCl, KCl. These are ionic solids
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    Agl crystallises in cubic close packed ZnS structure. What fraction of tetrahedral sites are occupied by Ag+ ions?
    In AgI, if there are nI- ions, there will be nAg+ ions. As I- ions form the lattice, number of tetrahedral voids = 2n.
    As there are nAg+     ions to occupy these voids, therefore fraction of tetrahedral voids occupied by Ag+ ions = n/2n = ½ = 50%.
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    Write the formula of a compound which is made of two elements A and B. Atom A forms close-packed lattice while atom B occupies all tetrahedral voids.
    For every atom in a close packed structure, there are two tetrahedral voids.

    Let the number of close packed spheres be N, then:
    The number of octahedral voids generated = N
    The number of tetrahedral voids generated = 2N

    Therefore formula of the compound is AB2
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    How many octahedral voids are there in 1 mole of a compound having cubic closed packed structure? 

    There are 1 mole of octhahedral voids in every one mole ofthe compound cotaining ccp structure.
    since number of particles present in 1 mole compound =6.022 x 1023 
    we know that number of octahedral voids=number of atoms in structure.
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