solution:
we have given
Density of element,
Cell edge a= 314pm or 3.14 x 10-10 cm
Atomic mass
The structure of the crystal lattice is B.C.C.
solution:
we have given a= 2.88A0
Density = 7.20g cm-3
mass = 100g
Volume of the unit cell =
Volume of 100g of the metal
No. of unit cell in
Solution:
We have given
volume of the unit cell = (5 x 10-8cm)3 = 1.25 x 10-22cm3
Density of FeO = 4g cm-3
Density,
Each unit cell has four units of FeO. So it has four Fe2+ and four O2– ions.