Hydrogen ion concentration in mol / L in a solution of pH = 5.4 will be

  • 3.98 x 108

  • 3.88 x 106

  • 3.68 x 10-6

  • 3.68 x 10-6


D.

3.68 x 10-6

pH = - log (H+ )

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The exothermic formation of ClF3 is represented by the equation
Cl subscript 2 left parenthesis straight g right parenthesis space plus space 3 straight F subscript 2 space left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon with space space space space space space space on top space 2 ClF subscript 3 space left parenthesis straight g right parenthesis space semicolon space increment rH space equals negative 329 space kJ
Which of the following will increase the quantity of ClF3 in an equilibrium mixture of Cl2, F2 and ClF3?

  • Increasing the temperature

  • Removing Cl2

  • Increasing the volume of the container

  • Increasing the volume of the container


D.

Increasing the volume of the container

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For a spontaneous reaction the ∆G, equilibrium constant (K) and Eocell will be respectively 

  • -ve, >1, +ve

  • +ve, >1, -ve

  • -ve, <1, -ve

  • -ve, <1, -ve


A.

-ve, >1, +ve

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What is the conjugate base of OH-?

  • O2

  • H2O

  • O-

  • O-


D.

O-

OH-→ O-2 + H+

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For the reaction
2 NO subscript 2 space left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon with space space space space space on top space 2 NO subscript space left parenthesis straight g right parenthesis end subscript space plus space straight O subscript 2 left parenthesis straight g right parenthesis
left parenthesis straight K subscript straight c space equals 1.8 space straight x space 10 to the power of negative 6 end exponent space at space 184 to the power of straight o space straight C right parenthesis
left parenthesis straight R space equals space 0.0831 space kJ divided by left parenthesis mol. straight K right parenthesis
When Kp and Kc are compared at 184oC, it is found that

  • Kp is greater than Kc

  • Kp is less than Kc

  • Kp = Kc

  • Kp = Kc


A.

Kp is greater than Kc

Kp = Kc RT∆n n =1
Kp > Kc

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