Which one of the following statements is not true?

  • Concentration of DO below 6 ppm is good for the growth of fish

  • Clean water would have a BOD value of less than 5 ppm

  • Oxides of sulphur, nitrogen and carbon are the most widespread air pollutant

  • Oxides of sulphur, nitrogen and carbon are the most widespread air pollutant


A.

Concentration of DO below 6 ppm is good for the growth of fish

The growth of fish is inhibited if the concentration of DO is below 6 ppm.

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Mole fraction of the solute in a 1.00 molal aqueous solution is 

  • 0.0177

  • 0.0344

  • 1.7700

  • 1.7700


A.

0.0177

1.00 molal aqueous solution = 1.0 mole in 1000 g water nsolute = 1; Wsolvent = 1000g

nsolvent = 1000/18 = 55.56

Xsolute = 1/ 1+ 55.56 = 0.0177

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6.02 x 1020 molecules of urea are present in 100 mL of its solution. The concentration of solution is

  • 0.02 M

  • 0.01 M

  • 0.001 M

  • 0.001 M


B.

0.01 M

Given, number of molecules of urea =6.02 x 1020
therefore ,Number of moles

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How many grams of the concentrated nitric solution should be used to prepare 250 mL o 2.0M HNO3 ? The concentrated acid is 70% HNO3.

  • 45.0 g conc. HNO3

  • 90.0 g conc. HNO3

  • 70.0 g conc. HNO3

  • 70.0 g conc. HNO3


A.

45.0 g conc. HNO3

Given, molarity of solution = 2
Volume of solution = 250 mL = 250/1000 = 1/4 L
Molar mass of 

HNO3 = 1+14+3 x 16 = 63 g mol-1
therefore, Molarity

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In the Kjeldahl's method for estimation of nitrogen present in a soil sample, ammonia evolved from 0.75 g of sample neutralised 10 mL of 1 M H2SO4.The percentage of nitrogen in the soil is

  • 37.33

  • 45.33

  • 35.33

  • 35.33


B.

45.33

In Kjeldahl's method, percentage of N is given by 

 

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