CBSE
Gujarat Board
Haryana Board
Class 10
Class 12
The angular momentum of electrons in d orbital is equal to
0 h
A.
Angular momentum of electrons in d- orbital isÂ
Angular momentum of electrons in d- orbital isÂ
Calculate the energy in joule corresponding to light of wavelength 45mm: (Planck's constant h=6.63 x10^{-34})Js; speed of light c= 3 x 10^{8} ms^{-1})
6.67 x 10^{15}
6.67 x 10^{11}
4.42 x 10^{-15}
4.42 x 10^{-18}
D.
4.42 x 10^{-18}
The wavelengthÂ of light isÂ related to its energy by the equation,
The wavelengthÂ of light isÂ related to its energy by the equation,
What is the maximum number of orbitals that can be identified with the following quantum numbers?
n=3,Â l =1, m_{1} = 0
1
2
3
4
A.
1
The value of n=3 andÂ l =1 suggest that it is a 3p orbital while the value of m_{1} = 0 [magnetic quantum number] shows that the given 3p orbital is 3p_{z} in nature.
Hence, the maximum number of orbitals identified by the given quantum number is only 1, i.e. 3p_{z}.
The value of n=3 andÂ l =1 suggest that it is a 3p orbital while the value of m_{1} = 0 [magnetic quantum number] shows that the given 3p orbital is 3p_{z} in nature.
Hence, the maximum number of orbitals identified by the given quantum number is only 1, i.e. 3p_{z}.