﻿ Following are the marks scored by 30 students in a test out of 40 marks. Using tally marks prepare a frequency table: 30 18 27 15 25 28 15 30 35 36 25 30 20 28 17 30 36 35 35 18 30 17 30   25 36 28 25 25 18 16 from Mathematics Data Handling Class 8 Manipur Board

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# Following are the marks scored by 30 students in a test out of 40 marks. Using tally marks prepare a frequency table: 30 18 27 15 25 28 15 30 35 36 25 30 20 28 17 30 36 35 35 18 30 17 30   25 36 28 25 25 18 16

Using tally marks, the required frequency is as given below:

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Present the following data in the form of a grouped frequency distribution table having 6 classes of equal size (one of the class being 40–48):
 30 39 58 17 34 50 23 37 42 49 55 59 19 28 47 49 18 60 56 36 58 35 55 37 25 34 39 61 53 33 36 53 61 62 39 53 21 18 28 23

The highest observation = 61.
The lowest observation = 17.
One of the class intervals = 40–48.
Class size = Upper class limit - Lower class limit = 48 – 40 = 8
∴ The appropriate classes can be:
16–24, 24–32, 32–40, 40–48, 48–56, 56–64
Thus, the frequency distribution table for the above data can be:

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(i) In which age group are the maximum number of people?
(ii) How many people are there is the ‘0-14 years’ group?
(iii) Find the central angle of the sector corresponding to the age group ‘15-60 years'.

Detailed solution not provided.
Ans. (i) 15-60 years
(ii) 30 thousand
(iii)

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The time spent by a child during a day:
(i) On which activity maximum number of hours are spent?
(ii) On which two activities does he spend equal number of hours?
(iii) Find the central angles for each sector of activities.

Detailed solution not provided.
Ans. (i) Sleep
(ii) Play and others
(iii Sleep , school , how work ; play , others

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On a particular day, the sales (in rupees) of different items of a store are given below:
Draw a pie-chart for the above data.

The total sale is 180°.
First we convert the sales of various items into central angles.

Now, the required pie chart is given below:

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