﻿ Find the solution of 3x-2=13. from Mathematics Linear Equations in One Variable Class 8 Manipur Board

## Chapter Chosen

Linear Equations in One Variable

## Book Store

Currently only available for.
`CBSE` `Gujarat Board` `Haryana Board`

## Previous Year Papers

Download the PDF Question Papers Free for off line practice and view the Solutions online.
Currently only available for.
`Class 10` `Class 12`

Find the solution of 3x-2=13.

3x-2=13

Transposing -2 to RHS, we have

Or                              3x=13+2

3x=15

Or                               x=               (Dividing both sides by 3)

Or                               x=5

1141 Views

If 1 is subtracted from both sides of x + 1 = 5, then we have:

• x = 5 – 1

• x + 2 4

• x = 1 – 6

A.

x = 5 – 1

153 Views

If 1 is added to both sides of x – 1 = 18, then we have:

• x – 1 + 1 = 18 – 1

• x – 1 + 1 = 18 + 1

• x – 1 + 1 = 18 – 2

B.

x – 1 + 1 = 18 + 1

125 Views

Solve:

Multiplying both sides by 6, we have             (∵   LCM of 3 and 6 is 6)

or             x + 3 + 6 = 2(6x-1)

or                x + 9 = 12x - 2

Transposing 9 to RHS and 12x to LHS, we have

x - 12x = -2 - 9
or                    -11x = -11

or                        (Dividing both sides by (-11))

∴                       x = 1

Check:         LHS =

RHS =

∴                          LHS = RHS

142 Views

The digits of a two digit number differ by 5. If the digits are interchanged and the resulting number is added to the original number, then we get 99. Find the original number.

Let the digit at unit place be 'x'.

∴                    The digit at the tens place = (x+5)

∴                                original number =10(x+5) + x

With interchange of digits, the new number = 10x + (x + 5)

Now, According to the condition, we have

[original number] + [New number] = 99

or         [10(x + 5) + x] + [10x + (x + 5)] = 99

or         [10x + 50 +x] + [10x + x + 5] = 99

or                        11x + 50 + 11x + 5 = 99

or                                       22x + 55 = 99

Transposing 55 to RHS, we have
22x = 99 - 55 = 44

Dividing both sides by 22, we have
x = 44 22 = 2

∴                                              x = 2

i.e.                                Unit place digit = 2

∴                                 Tens place digit = 2 + 5 = 7

Thus the original number = 72.

278 Views

If x – 1 = 6, then x = ?

• x = 6 + 1

• x = 6 - 1

• x = 1 – 6

A.

x = 6 + 1

125 Views