﻿ (a) Match the following figures with their respective areas in the box.(b) Write the perimeter of each shape. from Mathematics Mensuration Class 8 Manipur Board

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Mrs. Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of Rs 55 per m2.

∵  The given plot is a square with side as 25 m.
∴     Area of the plot = Side x Side
= 25 m x 25 m = 625 m2
∵  The constructed portion is a rectangle having length = 20 m and breadth = 15 m.
∴     Area of the constructed portion = 20 m x 15 m
= 300 m2
Now area of the garden = [Total plot area] - [Total constructed area]
= (625 - 300)m2
= 325 m2
∴  Cost of developing the garden =  Rs 55 x 325
= Rs 17, 875

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# (a) Match the following figures with their respective areas in the box.(b) Write the perimeter of each shape.

(a)

(b) (i) The given figure is a rectangle in which
Length = 14 cm
∵           Perimeter of a rectangle = 2 x [Length + Breadth]
∴        Perimeter of the given figure = 2 x [14 cm + 7 cm]
= 2 x 21 cm
= 42 cm

(ii)  The figure is a square  housing its side as 7 cm.
∵                Perimeter of a square = 4 x side
∴         Perimeter of the given figure = 4 x 7 cm
= 28 cm.

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The shape of a garden is rectangular in the middle and semi-circular at the ends as shown in the diagram. Find the area and the perimeter of this garden. [Length of rectangle is 20 - (3.5 + 3.5) meters.]

For the semi-circular part:
Diameter of the semi-circle = 7 m
∴  Radius of the semi-circle =
Area of the 2 semi-circles =

Also, perimeter of the 2 semicircles =

= 22 m
For rectangular part:
Length of the rectangle = 20 - (3.5 + 3.5) m
= 13 m
Breadth of the rectangle = 7 m
∴                                                     Area = Length x Breadth
= 13 m x 7 m
= 91 m2
Perimeter = 2 x [Length + Breadth]
= 2 x [13 m + 0 m]
= 2 x  13 m
= 26 m
Now, Area of the garden = (38.5 + 91)m2
= 129.5 m2
Perimeter of the garden = 22 m + 26 m
= 48 m

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A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles area required to cover a floor of area 1080 m2?
(If required you can split the tiles in whatever way want to fill up the corners.)

Area of a parallelograms = Base x Corresponding height
Area of a tile =
∴         Area of the floor  = 1080 m2
Now, number of tiles =

=
= 45000 tiles

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A square and a rectangular field with measurements as given in the figure have the same perimeter. Which field has a larger area?

(a) Side of the square = 60 m
∴        Its perimeter = 4 x side
= 4 x 60 m
= 240 m
Area of the square = Side x Side
= 60 m x 60 m
= 3600 m2
(b) ∵   Perimeter of the rectangle = Perimeter of the given square
∴   Perimeter of the rectangle = 240 m
or    2 x [Length + Breadth] = 240 m
or    2 x [80 m + Breadth] = 240 m
or               80 m + Breadth =
∴                         Breadth  = (120 - 80) m = 40 m
Now,               Area of the rectangle  = Length x Breadth
= 80 m x 40 m
= 3200 m2
Since,  3600 m2 > 3200 m2
∴  Area of the square field (a) is greater.

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