Find the area of a rhombus whose diagonals are 12 cm and 9.2 cm.

Let straight d subscript 1 space and space straight d subscript 2 be the diagonals of the rhombus.
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#6 {main}</pre> and straight d subscript 2 space equals space 9.2 space space cm

∵                       Area of rhombus = space 1 half cross times straight d subscript 1 cross times straight d subscript 2
∴       Area of the given rhombus = 1 half cross times 12 cross times 9.2 space cm squared
                                                  space space equals space 6 cross times 9.2 space cm squared space equals space 55.2 space cm squared
 
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Find the area of the following figures.


Solution not provided.
Ans. (a) 300 space straight m squared
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#6 {main}</pre>

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Fill in the blanks:


(a) Squre; space space straight a cross times straight a space equals space straight a squared       
(b) Triangle; 1 half straight x space straight b cross times straight h
(c) Parollelogram; b x h

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Find the area of quadrilateral PQRS shown in the figure:


Solution not provided.
Ans.  space 11 space cm squared
         

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Find the area the quadrilateral LMNOP (as shown in the figure).


Diagonal LN = 8 cm
Perpendicular MX = 4.5 cm
Perpendicular OY = 3.5 cm
∵   Sum of the perpendiculars = MX + OY = 4.5 cm + 3.5 cm = 8 cm
∴   Area of the quadrilateral = 1 half cross times (A diagonal ) x (Sum of the lengths of the perpendiculars on it from opposite vertices)
                                            equals 1 half cross times space 8 space cross times space 8 space cm squared space equals space 32 space cm squared
                                             

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