Write the following in the usual form.
(i) 10 x 5 + 6Â Â Â Â Â Â Â Â Â Â Â Â (ii)Â 100 x 7 + 10 x 1 + 8Â Â Â Â Â Â Â (iii) 100 x a + 10 x c + b
(i) 10 x 5 + 6 = 50 + 6 = 56
(ii) 100 x 7 + 10 x 1 + 8 = 700 + 10 + 8 = 718
(iii) 100 x a + 10 x c + b = 100 a + 10c + b = ![<pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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Check what the result would have been if sundaram had chosen the numbers shown below. 1. 27Â 2. 39Â 3. 64Â 4. 17
1.                     Chosen number = 27
        Number with reversed digits = 72
           Sum of the two numbers = 27 + 72 = 99
Now,                                  99 = 11[9]
                                             = 11[2 + 7]
                                             = 11(Sum of the digits of the chosen number)
2.                        Chosen number = 39
           Number with reversed digits = 93
               Sum of the two numbers = 39 + 93 = 132
Now,                            132 + 11 = 12
i,e,                   132 = 11[12]
                      = 11 [ 3 + 9]
                      = 11 [ Sum of the digits of the chosen number]           Â
3. Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Chosen number = 64
            Number with reversed digits = 46
                               Sum  = 64 + 46 = 110
Now, Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 110 = 11[10]
                              = 11[6 + 4]
                          = 11[ Sum of the digits of the chosen number Â
4.                         Chosen number   = 17
            Number with reversed digits    = 71
                                                       Sum  = 17 + 71 = 88
Now,                                                   88   = 11[8]
                                                                = 11[1+7]
                                                  = 11[Sum of the digits of the chosen number]
                         Â
Check what the result would have been if Minakshi had chosen the numbers shown below. In each case keep a record of the quotient obtained at the end.
1. 132Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Chosen number = 132
                           Reversed number = 231
                                    Difference = 231 - 132
                                                   = 99
We have                         99 + 99 = 1, remainder = 0
2. 469                      Chosen number = 469
                             Reversed number = 964
                                      Difference = 964 - 469 = 495
We have                          495 + 99 = 5, remainder = 0
3.                            Chosen number = 737
                            Reversed number = 737
                         We have dirrerence = 737 - 737 = 0
                                             0 + 99 = 0, remainder = 0
4.                             Chosen number  = 901
                              Reversed number = 109
                                       Differende = 901 - 109
                                                      = 792
        We have              792 + 99 = 8, remainder = 0
Forming three digit number with given three dgits.
Check what result would have been if Sundaram had chosen the numbers shown. 1.17Â 2.21Â 3.96Â 4.37.
1.                          Chosen number = 17
            Number with reversed digits = 71
                                   Difference = 71 - 17 = 54
                                                  = 9 x [6]
       Â
2.                               Chosen number = 21
                      Number with reversed digits = 12
                                            Difference = 21 - 12 = 9
                                                           = 9 x [1]
          = 9 x [Difference between the digits of the chosen number (2 - 1 = 1)]
3.                     Chosen number = 96
        Number with reversed digits = 69
                              Difference = 96 - 69 = 27
                                             = 9 x [3]
= 9 x [Difference between the digits of the chosen number (9 - 6)]
4.                                 Chosen number = 37
                   Number with reversed digits = 73
                                           Difference = 73 - 37 = 36
                                                         = 9 x [4]
     = 9 x [Difference between the digits of the chosen number (7 - 3 = 4)]
Write the following numbers in generalized form.
(i) 25Â (ii) 73Â (iii) 129Â (iv) 302
Â
(i)Â Â Â Â Â Â 25 = 20 + 5
              = 10 x 2 + 5 x 1 = 10 x 2 + 5
(ii)Â Â Â Â Â Â 73 = 70 + 3
               = 10 x 7 + 3 x 1 = 10 x 7 + 3
(iii)Â Â Â Â Â 129 = 100 + 20 + 9
               = 100 x 1 + 20 x 2 + 1 x 9 = 100 x 1 + 10 x 2 + 9
(iv)Â Â Â Â Â Â 302 = 100 x 3 + 10 x 0 + 1 x 2 = 300 + 0 + 2
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