Subject

Mathematics

Class

CBSE Class 12

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Sample Papers

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 Multiple Choice QuestionsLong Answer Type

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31.

Using integration, find the area of the region enclosed between the two circles:
straight x squared plus straight y squared space equals space 4 space and space left parenthesis straight x minus 2 right parenthesis squared plus straight y squared space equals space 4.


Given equations of the circles are:
straight x squared plus straight y squared space equals space 4 space space space... left parenthesis 1 right parenthesis
left parenthesis straight x minus 2 right parenthesis squared plus straight y squared space equals space 4 space... left parenthesis 2 right parenthesis
Equation (1) is a circle with centre O at the origin and radius 2. Equation (2) is a circle with centre C(2, 0) and radius 2.
Solving (1) and (2), we have:
left parenthesis straight x minus 2 right parenthesis squared plus straight y squared space equals space straight x squared plus straight y squared
straight x squared minus 4 straight x plus 4 plus straight y squared space equals space straight x squared plus straight y squared
straight x space equals space 1
This gives straight y equals plus-or-minus square root of 3
Thus, the points of intersection of the given circles are straight A open parentheses 1 comma space square root of 3 close parentheses space and space straight A apostrophe left parenthesis 1 comma space minus square root of 3 right parenthesis space as space shown space in space the space figure. space

Required area
 = Area of the region OACA'O
 = 2[area of the region ODCAO] 
 =2[area of the region ODAO + area of the region DCAD]
equals 2 open square brackets integral subscript 0 superscript 1 ydx plus integral subscript 1 superscript 2 ydx close square brackets
equals 2 open square brackets integral subscript 0 superscript 1 square root of 4 minus left parenthesis straight x minus 2 right parenthesis squared end root dx plus integral subscript 1 superscript 2 square root of 4 minus straight x squared end root dx close square brackets
equals 2 open square brackets 1 half left parenthesis straight x minus 2 right parenthesis square root of 4 minus left parenthesis straight x minus 2 right parenthesis squared end root plus 1 half cross times 4 sin to the power of negative 1 end exponent open parentheses fraction numerator straight x minus 2 over denominator 2 end fraction close parentheses close square brackets subscript 0 superscript 1 plus 2 open square brackets 1 half straight x square root of 4 minus straight x squared end root plus 1 half cross times 4 sin to the power of negative 1 end exponent straight x over 2 close square brackets subscript 1 superscript 2
equals open square brackets left parenthesis straight x minus 2 right parenthesis square root of 4 minus left parenthesis straight x minus 2 right parenthesis squared end root plus 4 sin to the power of negative 1 end exponent open parentheses fraction numerator straight x minus 2 over denominator 2 end fraction close parentheses close square brackets subscript 0 superscript 1 plus open square brackets straight x square root of 4 minus straight x squared end root plus 4 sin to the power of negative 1 end exponent straight x over 2 close square brackets subscript 1 superscript 2
equals open square brackets negative square root of 3 plus 4 sin to the power of negative 1 end exponent open parentheses fraction numerator negative 1 over denominator 2 end fraction close parentheses minus 4 sin to the power of negative 1 end exponent left parenthesis negative 1 right parenthesis close square brackets plus open square brackets 4 sin to the power of negative 1 end exponent 1 minus square root of 3 minus 4 sin to the power of negative 1 end exponent 1 half close square brackets
equals open square brackets open parentheses negative square root of 3 minus 4 cross times straight pi over 6 close parentheses plus 4 cross times straight pi over 2 close square brackets plus open square brackets 4 cross times straight pi over 2 minus square root of 3 minus 4 cross times straight pi over 6 close square brackets
equals fraction numerator 8 straight pi over denominator 3 end fraction minus 2 square root of 3


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32.

Show that the differential equation 2 ye to the power of straight x divided by straight y end exponent dx plus left parenthesis straight y minus 2 straight x space straight e to the power of straight x divided by straight y end exponent right parenthesis space dy space equals space 0 is homogeneous. Find the particular solution of this differential equation, given that x = 0 when y = 1.

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33.

Find the vector equation of the plane passing through three points with position vectors straight i with hat on top plus straight j with hat on top minus 2 straight k with hat on top comma space 2 straight i with hat on top minus straight j with hat on top plus straight k with hat on top space and space straight i with hat on top plus 2 straight j with hat on top plus straight k with hat on top. Also, find the coordinates of the point of intersection of this plane and the line straight r with rightwards arrow on top space equals 3 straight i with hat on top minus straight j with hat on top minus straight k with hat on top plus straight lambda open parentheses 2 straight i with hat on top minus 2 straight j with hat on top plus straight k with hat on top close parentheses.

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34.

A cooperative society of farmers has 50 hectares of land to grow two crops A and B. The profits from crops A and B per hectare are estimated as Rs 10,500 and Rs 9,000 respectively. To control weeds, a liquid herbicide has to be used for crops A and B at the rate of 20 litres and 10 litres per hectare, respectively. Further not more than 800 litres of herbicide should be used in order to protect fish and wildlife using a pond which collects drainage from this land. Keeping in mind that the protection of fish and other wildlife is more important than earning profit, how much land should be allocated to each crop so as to maximize the total profit? Form an LPP from the above and solve it graphically. Do you agree with the message that the protection of wildlife is utmost necessary to preserve the balance in environment?

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35.

Assume that the chances of a patient having a heart attack is 40%. Assuming that a meditation and yoga course reduces the risk of heart attack by 30% and prescription of certain drug reduces its chance by 25%. At a time a patient can choose any one of the two options with equal probabilities. It is given that after going through one of the two options, the patient selected at random suffers a heart attack. Find the probability that the patient followed a course of meditation

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