Subject

Mathematics

Class

CBSE Class 12

Pre Boards

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Sample Papers

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 Multiple Choice QuestionsLong Answer Type

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31. Let space straight a with rightwards arrow on top space equals space straight i with hat on top space plus straight j with hat on top space plus stack straight k comma with hat on top space
straight b with rightwards arrow on top space equals space straight i with hat on top space and
straight c with rightwards arrow on top space equals space straight c subscript 1 straight i with hat on top space plus straight c subscript 2 straight j with hat on top space plus straight c subscript 3 straight k with hat on top space space then
a) Let c1 = 1 and c2 = 2, find c3 which makes straight a with rightwards arrow on top space comma straight b with rightwards arrow on top space and space straight c with rightwards arrow on top coplanar.
b) If c2 = –1 and c3 = 1, show that no value of c1 can make straight a with rightwards arrow on top space comma straight b with rightwards arrow on top space and space straight c with rightwards arrow on top coplanar.


straight a with rightwards arrow on top space equals space straight i with hat on top space plus straight j with hat on top plus straight k with hat on top comma
straight b with hat on top space equals space straight i with hat on top
straight c with hat on top space equals space straight c subscript 1 straight i with hat on top space plus space straight c subscript 2 straight j with hat on top space plus straight c subscript 3 straight k with hat on top
then,

a) c1 = 1 and c2 = 2,
straight c with hat on top space equals space straight c subscript 1 straight i with hat on top space plus space straight c subscript 2 straight j with hat on top space plus straight c subscript 3 straight k with hat on top
For vectors to be coplanar scalar triple product should be equal to zero.
therefore space straight a with rightwards arrow on top space left parenthesis straight b with rightwards arrow on top space straight x space straight c with rightwards arrow on top right parenthesis space equals space 0
rightwards double arrow space left parenthesis straight i with hat on top space plus straight j with hat on top space plus straight k with hat on top right parenthesis. space left square bracket straight i with hat on top space straight x left parenthesis straight i with hat on top space plus 2 straight j with hat on top space plus straight c subscript 3 straight k with hat on top right parenthesis right square bracket space equals space 0
rightwards double arrow space left parenthesis straight i with hat on top space plus straight j with hat on top space plus straight k with hat on top right parenthesis. left parenthesis negative straight c subscript 3 straight j with hat on top space plus 2 straight k with hat on top right parenthesis space equals space 0
rightwards double arrow space 0 minus straight c subscript 3 space plus 2 space equals 0
rightwards double arrow straight C subscript 3 space equals space 2
b) c2 = –1 and c3 = 1
straight c with rightwards arrow on top space equals space straight c subscript 1 straight i with hat on top minus straight j with hat on top plus space straight k with hat on top
Let space straight a with rightwards arrow on top comma space straight b with rightwards arrow on top space and space straight c with rightwards arrow on top space be space coplanar.
For space vectors space to space be space coplanar space scalar space triple space product space should space be space equal space to space zero.
therefore space straight a with rightwards arrow on top left parenthesis straight b with rightwards arrow on top space straight x space straight c with rightwards arrow on top right parenthesis space equals space 0
left parenthesis straight i with hat on top space plus straight j with hat on top plus straight k with hat on top right parenthesis. open square brackets straight i with hat on top space straight x space left parenthesis straight c subscript 1 straight i with hat on top space minus straight j with hat on top plus straight k with hat on top close square brackets
space open square brackets straight i with hat on top space straight x space left parenthesis straight c subscript 1 straight i with hat on top space minus straight j with hat on top plus straight k with hat on top close square brackets space open vertical bar table row cell straight i with hat on top end cell cell straight j with hat on top end cell cell straight k with hat on top end cell row 1 0 0 row cell straight c subscript 1 end cell cell negative 1 end cell 1 end table close vertical bar
equals space straight i with hat on top space left parenthesis 0 minus 0 right parenthesis minus straight j with hat on top space left parenthesis 1 minus 0 right parenthesis space plus straight k with hat on top left parenthesis negative 1 minus 0 right parenthesis
space equals negative straight j with hat on top minus straight k with hat on top
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32.

Find the area bounded by the circle x2 + y2 = 16 and the line √3y=x in the first quadrant, using integration.

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33.

Using integration, find the area of region bounded by the triangle whose vertices are (–2, 1), (0, 4) and (2, 3).

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