Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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11.

The area bounded between the parabolas x2=y/4 and x2 = 9y, and the straight line y = 2 is

  • 20 square root of 2
  • fraction numerator 10 space square root of 2 over denominator 3 end fraction
  • fraction numerator 20 space square root of 2 over denominator 3 end fraction
  • fraction numerator 20 space square root of 2 over denominator 3 end fraction


C.

fraction numerator 20 space square root of 2 over denominator 3 end fraction


Required space area
space equals space 2 integral subscript 0 superscript 2 space open parentheses 3 square root of straight y space minus fraction numerator square root of straight y over denominator 2 end fraction close parentheses space dy space equals space 2 integral subscript 10 superscript 2 open parentheses 5 over 2 square root of straight y close parentheses space dy
equals space open square brackets fraction numerator straight y to the power of 3 divided by 2 end exponent over denominator 3 divided by 2 end fraction close square brackets subscript straight y equals 0 end subscript superscript straight y space equals 2 end superscript space equals space 10 over 3 space left parenthesis 2 to the power of 3 divided by 2 end exponent minus 0 right parenthesis space equals space fraction numerator 20 square root of 2 over denominator 3 end fraction
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12.

If the line fraction numerator straight x minus 1 over denominator 2 end fraction space equals space fraction numerator straight y plus 1 over denominator 3 end fraction space equals space fraction numerator straight z minus 1 over denominator 4 end fraction and fraction numerator straight x minus 3 over denominator 1 end fraction space equals fraction numerator straight y minus straight k over denominator 2 end fraction space equals space straight z over 1 intersect, then k is equal to

  • -1

  • 2/9

  • 9/2

  • 9/2

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13.

Three numbers are chosen at random without replacement from {1, 2, 3, ...... 8}. The probability that their minimum is 3, given that their maximum is 6, is

  • 3/8

  • 1/5

  • 1/4

  • 1/4

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14.

If z ≠ 1 and fraction numerator straight z squared over denominator straight z minus 1 end fraction is real, then the point represented by the complex number z lies

  • either on the real axis or on a circle passing through the origin

  • on a circle with centre at the origin

  • either on the real axis or on a circle not passing through the origin

  • either on the real axis or on a circle not passing through the origin

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15.

The length of the diameter of the circle which touches the x-axis at the point (1, 0) and passes through the point (2, 3) is

  • 10/3

  • 3/5

  • 6/5

  • 6/5

172 Views

16.

Let X = {1, 2, 3, 4, 5}. The number of different ordered pairs (Y, Z) that can be formed such that Y ⊆ X, Z ⊆ X and Y ∩ Z is empty, is

  • 52

  • 35

  • 25

  • 25

248 Views

17.

An ellipse is drawn by taking a diameter of the circle (x–1)2 + y2 = 1 as its semiminor axis and a diameter of the circle x2 + (y – 2)2 = 4 as its semi-major axis. If the centre of the ellipse is the origin and its axes are the coordinate axes, then the equation of the ellipse is

  • 4x2+ y2 = 4

  • x2 +4y2 =8

  • 4x2 +y2 =8

  • 4x2 +y2 =8

398 Views

18.

A line is drawn through the point (1, 2) to meet the coordinate axes at P and Q such that it forms a triangle OPQ, where O is the origin. If the area of the triangle OPQ is least, then the slope of the line PQ is

  • -1/4

  • -4

  • -2

  • -2

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19.

A spherical balloon is filled with 4500π cubic meters of helium gas. If a leak in the balloon causes the gas to escape at the rate of 72π cubic meters per minute, then the rate (in meters per minute) at which the radius of the balloon decreases 49 minutes after the leakage began is

  • 9/7

  • 7/9

  • 2/9

  • 2/9

1221 Views

20.

Let A = open square brackets table row 1 0 0 row 2 1 0 row 3 2 1 end table close square brackets. If u1 and u2 are column matrices such that Au1 = open square brackets table row 1 row 0 row 0 end table close square brackets and Au2 = open square brackets table row 0 row 1 row 0 end table close square brackets, then u1 +u2 is equal to

  • open square brackets table row cell negative 1 end cell row 1 row 0 end table close square brackets
  • open square brackets table row cell negative 1 end cell row cell space space space 1 end cell row cell negative 1 end cell end table close square brackets
  • open square brackets table row cell negative 1 end cell row cell negative 1 end cell row 0 end table close square brackets
  • open square brackets table row cell negative 1 end cell row cell negative 1 end cell row 0 end table close square brackets
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