Subject

Chemistry

Class

NEET Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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21.

When excess of NaOH solution is added to aqueous solution of iodine, the colour of solution becomes

  • blue

  • yellow

  • colourless

  • pale green


C.

colourless

The colour of solution is due to iodine present in it. When NaOH solution is added, it reacts with L, and solution becomes colourless.

I2 + 2NaOH Cold  NaI + NaIO + H2O

3I2 + 6NaOHHot  5NaI + NaIO3 +3H2O


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22.

Which of the following statements is incorrect regarding the reaction?

CH3CHO + [Ag(NH3)2] + OHCH3COO- + Ag

  • The equivalent weight of CH3CHO is 22

  • Three moles of OH- are required in the above D reaction

  • CH3CHO is an oxidising agent

  • Reduction of [Ag(NH3)2] occurs


23.

In the reaction,

How many electron donating groups are attached with the carbon atom of unsaturated part of the product 'B' ?

  • Two

  • Three

  • Four

  • None of these


24.

The magnitude of screening effect depends upon the number of

  • inner electrons

  • outer electrons

  • bond order

  • Both (a) and (b)


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25.

Duma's method involves the determination of nitrogen content in the organic compound in the form of

  • NH3

  • N2

  • NaCN

  • (NH4)2SO4


26.

Which of the following statement(s) is not correct?

  • Suspended particulate matter is an important pollutant released by diesel vehicles

  • Soot particles (size < 5μ) cause fibrosis of the lung living

  • H2SO4 particulates have size of 500- 1000 nm

  • Photochemical smog is formed by oxides of sulphur, smoke and dust particles


27.

The value of n in

MnO4- + 8H+ ne-  Mn2+ + 4H2O is

  • 5

  • 4

  • 2

  • 3


28.

Solid NaHCO3 will be neutralised by 40.0 mL of 0.1 M H2SO4 solution. What would be the weight of solid NaHCO3 in gram?

  • 0.672 g

  • 6.07 g

  • 17 g

  • 20 g


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29.

For the cell reaction,

Pb + Sn2+   Pb2+ + Sn

Given that, Pb  Pb2+, E° = 0.13 V

Sn2+ +2e-  Sn, E° = -0.14 V

What would be the ratio of cation concentration for which E = 0 ?

  • 14

  • 12

  • 13

  • 11


30.

[CuCl4]2- exists while [CuI4]2- does not exist, because

  • I- is stronger reductant than Cl-

  • I- is weaker reductant than Cl-

  • I- is stronger oxidant than Cl-

  • None of the above


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