Phenyl magnesium bromide reacts with methanol to give
a mixture of anisole and Mg(OH)Br
a mixture of benzene and Mg(OMe)Br
a mixture of toluene and Mg(OH)Br
a mixture of toluene and Mg(OH)Br
B.
a mixture of benzene and Mg(OMe)Br
Tertiary alkyl halides are practically inert to substitution by SN2 mechanism because of
insolubility
instability
inductive effect
inductive effect
The IUPAC name of
1, 1-diethyl-2-dimethylpentane
4, 4-dimethyl-5, 5-diethylpentane
5, 5-diethyl-4, 4-dimethylpentane
5, 5-diethyl-4, 4-dimethylpentane
Presence of a nitro group in a benzene ring -
activates the ring towards electrophilic substitution
renders the ring basic
deactivates the ring towards nucleophilic substitution
deactivates the ring towards nucleophilic substitution
2 methylbutane on reacting with bromine in the presence of sunlight gives mainly
1 – bromo -2 - methylbutane
2 – bromo -2 - methylbutane
2 – bromo -3 - methylbutane
2 – bromo -3 - methylbutane
The IUPAC name of the compound shown below is
2-bromo-6-chlorocyclohex-1-ene
6-bromo-2-chlorocyclohexene
3-bromo-1-chlorocyclohexene
3-bromo-1-chlorocyclohexene
Which of the following is the correct order of decreasing SN2 reactivity?
RCH2X > R3CX > R2CHX
RCH2X > R2CHX > R3CX
R3CX > R2CHX >RCH2X
R3CX > R2CHX >RCH2X
Reaction of trans-2-phenyl-1-bromocyclopentane on reaction with alcoholic KOH produces
4-phenylcyclopentene
2-phenylcyclopentene
1-phenylcyclopentene
1-phenylcyclopentene
HBr reacts with CH2 = CH – OCH3 under anhydrous conditions at room temperature to give
CH3CHO and CH3Br
BrCH2CHO and CH3OH
BrCH2 – CH2 – OCH3
H3C – CHBr – OCH3