There are deer and peacocks in a zoo. By counting heads they are 80. The number of their legs is 200. How many peacocks are there?
20
60
50
50
B.
60
Let the number of deer and peacock be x and y.
So, as per question
x + y = 80 ...(i)
4x + 2y = 200
or 2x + y = 100 ...(ii)
Solving the Eq.(i) and Eq. (ii), we get, x = 20, y = 60
Hence, the number of peacock = 60