The cost of 2 kg of apples and 1 kg of grapes on a day was found to be Rs. 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs. 300. Represent the situation algebraically and geometrically.

Let the cost of 1 kg of apples be Rs. x and of 1 kg of grapes be Rs. y. So, algebraic representation

<>2x + y = 160

4x + 2y = 300

⇒ 2x + y = 150

Graphical representation, we have

2x + y = 160

⇒ y = 160 - 2x

We have,

2x + y = 150

⇒ y = 150 - 2x

When we plot the graph of the equation we find that two lines do not intersect i.e. they are parallel.

Let the cost of 1 kg of apples be Rs. x and of 1 kg of grapes be Rs.

Fig. 3.3.

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The cost of 2 kg of apples and 1 kg of grapes on a day was found to be Rs. 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs. 300. Represent the situation algebraically and geometrically.