Important Questions of રસાયણિક ગતિકી for JEE Chemistry | Zigya

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Gujarati JEE Chemistry : રસાયણિક ગતિકી

Multiple Choice Questions

11.

 

પ્રક્રિયા : BrO3-(aq) + 5Br-(aq) + 6H(aq) rightwards arrow3Br2(1) + 3H2O(1) માં Brના વપરાશનો દર 1.5 × 10-2Ms-1 àª›à«‡. H ના વપરાશનો દર અને Br2 ઉત્પન્ન થવાનો દર અનુક્રમે .......... થશે.

  •  

    (5 × 6) 1.5 × 10-2, (3 × 6) 1.5 × 10-2

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    (5 + 6) 1.5 × 10-2, (3 + 6) 1.5 × 10-2

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    open parentheses 6 over 5 close parentheses space 1.5 space cross times space 10 to the power of negative 2 end exponent comma space open parentheses 3 over 5 close parentheses space 1.5 space cross times space 10 to the power of negative 2 end exponent

  •  

    open parentheses 5 over 6 close parentheses space 1.5 space cross times space 10 to the power of negative 2 end exponent comma space open parentheses 5 over 3 close parentheses space space 1.5 space cross times space 10 to the power of negative 2 end exponent


12.

 

N2O4(g) rightwards arrow 2NO2(g) àªªà«àª°àª•à«àª°àª¿àª¯àª¾ દરમિયાન N2Oનું દબાણ 30 મિનિટમાં 0.3 વાતા.થી 0.32  àªµàª¾àª¤àª¾ થાય છે. NO2  ના ઉત્પાદનનો વેગ જણાવો.

  •  

    0.012 àªµàª¾àª¤àª¾. મિનિટ-1

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    0.24 àªµàª¾àª¤àª¾. મિનિટ-1

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    0.006 àªµàª¾àª¤àª¾. મિનિટ-1

  •  

    0.003 àªµàª¾àª¤àª¾. મિનિટ-1


13. H2  + I2  ⇌ 2HI negative fraction numerator straight d left square bracket straight H subscript 2 right square bracket over denominator dt end fraction space equals space minus fraction numerator straight d left square bracket straight I subscript 2 right square bracket over denominator dt end fraction space equals space plus space fraction numerator straight d left square bracket HI right square bracket over denominator dt end fractionપ્રક્રિયા માટે સાચો પ્રક્રિયાવેગ કયો છે ?
  • negative fraction numerator straight d left square bracket straight H subscript 2 right square bracket over denominator 2 dt end fraction space equals space minus fraction numerator straight d left square bracket straight I subscript 2 right square bracket over denominator 2 dt end fraction space equals space plus space fraction numerator straight d left square bracket HI right square bracket over denominator dt end fraction
  • negative fraction numerator straight d left square bracket straight H subscript 2 right square bracket over denominator 2 dt end fraction space equals space minus fraction numerator straight d left square bracket straight I subscript 2 right square bracket over denominator 2 dt end fraction space equals space plus space fraction numerator straight d left square bracket HI right square bracket over denominator 4 dt end fraction
  • negative fraction numerator straight d left square bracket straight H subscript 2 right square bracket over denominator dt end fraction space equals space minus fraction numerator 2 straight d left square bracket straight I subscript 2 right square bracket over denominator dt end fraction space equals space plus space fraction numerator 2 straight d left square bracket HI right square bracket over denominator dt end fraction

14. પ્રક્રિયા H + OH- rightwards arrow H2O માં H આયનની સાંદ્વતામાં 0.02Mજેટલો ઘટાડો થતાં બે નેનો સેકન્ડ લાગે છે. પ્રક્રિયાનો સરેરાશ વેગ કેટલો હશે ?
  • 2 Ms-1

  • 1 × 107 Ms-1

  • 0.02 × 109 Ms-1

  • આપેલ પૈકી એક પણ નહી 


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15.

 

bold N subscript bold 2 bold space bold plus bold space bold 3 bold H subscript bold 2 bold space bold rightwards harpoon over leftwards harpoon bold space bold 2 bold NH subscript bold 3 bold spaceપ્રક્રિયામાં હાઇડ્રોજનની સાંદ્વતામાં થતો ફેરફાર -0.3 × 10-4Ms-1 àª®àª³à«‡ છે. તે સમયે એમોનિયાની સાંદ્વતામાં થતો ફેરફાર = .......... . 

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    0.2 × 10-4

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    -0.2 × 10-4

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    0.1 × 10-4

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    0.3 × 10-4


16. bold plus bold 1 over bold 3 fraction numerator bold d bold left square bracket bold Br subscript bold 2 bold right square bracket over denominator bold dt end fraction bold space bold equals bold space bold minus bold space fraction numerator bold d bold left square bracket bold BrO subscript bold 3 to the power of bold minus bold right square bracket over denominator bold dt end fraction bold space bold equals bold space bold minus bold 1 over bold 5 fraction numerator bold d bold left square bracket bold Br to the power of bold minus bold right square bracket over denominator bold dt end fraction bold space bold equals bold space bold minus bold 1 over bold 6 fraction numerator bold d bold left square bracket bold H to the power of bold plus bold right square bracket over denominator bold dt end fraction bold spaceપ્રક્રિયાવેગ ધરાવતી પ્રક્રિયાનું સંતુલિત સમીકરણ ..... 
  • BrO subscript 3 to the power of minus subscript left parenthesis aq right parenthesis end subscript space plus space 5 Br to the power of minus subscript left parenthesis aq right parenthesis end subscript space plus space 6 straight H subscript left parenthesis aq right parenthesis end subscript space rightwards arrow space 3 Br subscript 2 left parenthesis aq right parenthesis end subscript
  • BrO subscript 3 to the power of minus subscript left parenthesis aq right parenthesis end subscript space plus space 5 Br to the power of minus subscript left parenthesis aq right parenthesis end subscript space plus space 6 straight H subscript left parenthesis aq right parenthesis end subscript space rightwards arrow space 3 Br subscript 2 left parenthesis aq right parenthesis end subscript space plus space 3 straight H subscript 2 straight O subscript left parenthesis 1 right parenthesis end subscript
  • Br subscript 2 left parenthesis aq right parenthesis end subscript space plus space BrO subscript 3 to the power of minus subscript left parenthesis aq right parenthesis end subscript space rightwards arrow space 5 Br to the power of minus subscript left parenthesis aq right parenthesis end subscript space plus space 6 straight H subscript left parenthesis aq right parenthesis end subscript
  • આપેલ પૈકી એક પણ નહી 


17. bold 2 bold A bold space bold plus bold space bold B bold space bold rightwards arrow bold space bold 2 bold C bold space bold plus bold space bold 2 bold D માટે નીચેના પૈકી કયું વિધાન ખોટું છે ?
  • C અને D ઉત્પન્ન થવાનો વેહ સરખો છે.

  • C ના ઉત્પાદનનોવેગ B ના વપરાશના વેગથી અડધો છે.

  • B ના વપરાશનો વેગ, A ના વપરાશના વેગથી ચોથા ભાગનો છે.

  • C ના ઉત્પાદનનો વેગ A ના વપરાશના વેગથી અડધો છે.


18.

 

પ્રક્રિયા : A + 2B rightwards arrowC + 2Dમાં t1  àª¸àª®àª¯à«‡ bold minus fraction numerator bold d bold left square bracket bold A bold right square bracket over denominator bold dt end fraction bold space bold equals bold space bold 2 bold. bold 6 bold space bold cross times bold space bold 10 to the power of bold minus bold 2 end exponent bold M bold space bold sec to the power of bold minus bold 1 end exponent àª›à«‡, તો tસમયે bold minus fraction numerator bold d bold left square bracket bold B bold right square bracket over denominator bold dt end fraction ........... થશે.a

  •  

    1.0 × 10-1

  •  

    6.5 × 10-3

  •  

    5.2 × 10-2

  •  

    આપેલ પૈકી એક પણ નહી 


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19.

 

પ્રક્રિયા : bold 2 bold N subscript bold 2 bold O bold space bold rightwards arrow bold space bold 4 bold NO subscript bold 2 bold space bold plus bold space bold O subscript bold 2 bold space àª¨à«àª‚ વેગ સમીકરણ ત્રણ પ્રકારે લખી શકાય છે, તો K અને K' તથા K અને K'' વચ્ચેનો સંબંધ કયો છે ?

fraction numerator bold minus bold d bold left square bracket bold N subscript bold 2 bold O subscript bold 5 bold right square bracket over denominator bold dt end fraction bold space bold equals bold space bold K bold left square bracket bold N subscript bold 2 bold O subscript bold 5 bold right square bracket bold space bold space fraction numerator bold d bold left square bracket bold NO subscript bold 2 bold right square bracket over denominator bold dt end fraction bold space bold equals bold space bold K bold apostrophe bold left square bracket bold N subscript bold 2 bold O subscript bold 5 bold right square bracket bold space bold space fraction numerator bold d bold left square bracket bold O subscript bold 2 bold right square bracket over denominator bold dt end fraction bold space bold equals bold space bold K bold apostrophe bold apostrophe bold left square bracket bold N subscript bold 2 bold O subscript bold 5 bold right square bracket

  •  

    K' = 2K, K'' = 2K

  •  

    K' = 2K, K'' = K

  •  

    K' = 2K, K'' = bold K over bold 2

  •  

    આપેલ પૈકી એક પણ નહી 


20.

 

bold 2 bold A bold space bold plus bold space bold B bold space bold rightwards arrow bold space bold 2 bold C bold space bold plus bold space bold 4 bold D àª®àª¾àª‚ ડ ના ઉત્પાદનનો વેગ 1.6 ×10-3Ms-1 àª›à«‡. આ પ્રક્રિયા માટે નીચેના પૈકી કયું વિધાન સાચું છે ?

  •  

    negative 1 half fraction numerator straight d left square bracket straight A right square bracket over denominator dt end fraction equals space 1.6 space 10 to the power of negative 3 end exponent Ms to the power of negative 1 end exponent

  •  

    fraction numerator straight d left square bracket straight C right square bracket over denominator dt end fraction equals space 8.0 space cross times 10 to the power of negative 4 end exponent Ms to the power of negative 1 end exponent

  •  

    negative fraction numerator straight d left square bracket straight B right square bracket over denominator dt end fraction space equals space 3.2 space cross times space 10 to the power of negative 3 end exponent Ms to the power of negative 1 end exponent

  •  

    આપેલ પૈકી એક પણ નહી 


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