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CBSE

Gujarati JEE Physics : કાયનેમેટિક્સ

Multiple Choice Questions

11. $bold rightwards arrow for bold A of$ તથા $bold rightwards arrow for bold B of$ બંનેને લંબ હોય, તેવો એકમ સદિશ ......

$fraction numerator rightwards arrow for straight A of minus rightwards arrow for straight B of over denominator AB end fraction$
$fraction numerator rightwards arrow for straight A of cross times rightwards arrow for straight B of over denominator ABcosθ end fraction$
$fraction numerator rightwards arrow for straight A of cross times rightwards arrow for straight B of over denominator ABsinθ end fraction$
$fraction numerator rightwards arrow for straight A of times rightwards arrow for straight B of over denominator ABsinθ end fraction$

12.

એક વ્યક્તિ સીધી રેખા પર 40 m અંતર કાપી જમણી તરફ 30 m અંતર કાંપે છે, તો આ દારમિયાન તેણે કાપેલા અંતર અને સ્થાનાંતરનો ગુણોત્તર ........ થશે.

0.75
1.4
1.33
1

13. $bold vertical line bold rightwards arrow for bold A of bold vertical line bold space bold equals bold space bold 4 bold comma bold space bold vertical line bold rightwards arrow for bold B of bold vertical line bold space bold equals bold space bold 2 bold. bold 5 bold comma bold space bold rightwards arrow for bold A of bold times bold rightwards arrow for bold B of bold space bold equals bold space bold 8 bold space bold તથ ા bold space bold rightwards arrow for bold A of bold space bold અન ે bold space bold rightwards arrow for bold B of$ વચ્ચેનો ખુણો લઘુકોણ હોય, તો $open parentheses bold rightwards arrow for bold A of bold cross times bold rightwards arrow for bold B of close parentheses$ ............. .

14. $bold rightwards arrow for bold A of bold space bold equals bold space bold 2 bold space bold i with bold hat on top bold space bold minus bold space bold 3 bold space bold j with bold hat on top bold space bold minus bold space bold k with bold hat on top$ અને $bold rightwards arrow for bold B of bold space bold equals bold space bold 4 bold space bold i with bold hat on top bold space bold plus bold space bold 3 bold space bold k with bold hat on top$ વડે રચાતા સમાંતરબાજુ ચતુષ્કોણનું ક્ષેત્રફળ લગભગ ....... એકમ

15. એક સાઇકલ સવાર પોતાને ગતિ કરવાના કુલ અંતરમાંથી ત્રીજા ભાગનું અંતર 12 kmh^-1જેટલી ઝડપથી અને બાકીનું અંતર 18 kmh^-¹ની ઝડપથી કાપે છે. તો તેની સરેરાશ ઝડપ ........... kmh^-1 થશે.

18
12
15.43
15

16. $bold 2 over bold 3 bold i with bold hat on top bold space bold plus bold space bold 1 over bold 3 bold j with bold hat on top bold space bold plus bold space bold m bold space bold k with bold hat on top$ એકમ સદિશ હોય, તો m = .......... .

$1 third$
$negative 1 third$
$2 over 3$
1

17. $bold rightwards arrow for bold A of bold space bold equals bold space bold 3 bold space bold i with bold hat on top bold space bold minus bold space bold 2 bold space bold j with bold hat on top bold space bold plus bold space bold k with bold hat on top bold space$ નો $bold rightwards arrow for bold B of bold space bold equals bold space bold i with bold hat on top bold space bold plus bold space bold j with bold hat on top bold space$ ની દિશામાંન ઘટક .......

1
$square root of 2$
$fraction numerator 1 over denominator square root of 2 end fraction$
$square root of 14$

18.

જોગર્સ પાર્કમાં એક માણસ 30 m ત્રિજ્યા ધરાવતા એક વર્તુળમય પથ પર બે પરિભ્રમણ પૂર્ણ કરે છે, તો આ દરમિયાન તેણે કાપેલ કુલ અંતર અને સ્થાનાંતરનો તફાવત .......... m થશે.

$30 space straight pi$
$60 space straight pi$
$120 space straight pi$
શૂન્ય

19. કોઈ એક વાહન જુદી જુદી ઝડપોથી જુદાં જુદાં અંતરો એક જ દિશામાં કાપે છે. આ વાહન માટે સરેરાશ ઝડપ ..... .

$straight d subscript 1 over straight t subscript 1 space plus space d subscript 2 over t subscript 2 space plus space fraction numerator d subscript 3 t subscript 3 over denominator t subscript 3 end fraction space plus space......$
$straight v subscript 1 space plus space straight v subscript 2 space plus space straight v subscript 3 space plus space.... space$
$fraction numerator straight v subscript 1 space plus space straight v subscript 2 space plus space straight v subscript 3 space plus space.... over denominator straight t subscript 1 space plus space straight t subscript 2 space plus space straight t subscript 3 space plus space.... end fraction$
$fraction numerator straight d subscript 1 space plus space straight d subscript 2 space plus space straight d subscript 3 straight d subscript 1 end subscript space plus space.... over denominator begin display style straight d subscript 1 over straight v subscript 1 end style plus space begin display style straight d subscript 2 over straight v subscript 2 end style space plus begin display style straight d subscript 3 over straight v subscript 3 end style plus.... end fraction$