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ગણિત ધોરણ 12 સિમેસ્ટર 4

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નીચે આપેલાં નિયત સંકલિતને સરવાળાના લક્ષ સ્વરૂપે મેળવો :

integral from 1 to 3 of space open parentheses straight x squared space plus space straight x close parentheses space dx


નીચે આપેલાં નિયત સંકલિતને સરવાળાના લક્ષ સ્વરૂપે મેળવો :
integral from negative 1 to 1 of space straight e to the power of straight x space dx


નીચે આપેલાં નિયત સંકલિતને સરવાળાના લક્ષ સ્વરૂપે મેળવો :
integral from 0 to 1 of space straight e to the power of 2 minus 3 straight x end exponent space dx


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નીચે આપેલાં નિયત સંકલિતને સરવાળાના લક્ષ સ્વરૂપે મેળવો :
integral from 1 to 2 of space 3 to the power of straight x space dx


અહી, વિધેય f(x) = 3x એ [1, 2] માં સતત છે.

[1, 2] નું સમાન લંબાઈના n ઉપાંતરાલોમાં વિભાજન કરતાં,

પ્રત્યેક ઉપાંતરાલની લંબાઈ straight h space equals space fraction numerator straight b space minus space straight a over denominator straight n end fraction space equals space fraction numerator 2 space minus space 1 over denominator straight n end fraction space equals space 1 over straight n થશે.

તેથી nh = 1 મળે. તથા જેમ straight n space rightwards arrow space infinity તેમ straight h space rightwards arrow space 0 થશે.


હવે, વ્યાખ્યા પ્રમાણે,

integral from 1 to 2 of space 3 to the power of straight x space dx space equals space limit as straight h rightwards arrow 0 of space straight h space sum from straight i space equals space 1 to straight n of space straight f open parentheses 1 space plus space ih close parentheses space space space space open parentheses because space straight a space equals space 1 close parentheses




              equals space limit as straight h rightwards arrow 0 of space straight h space sum from straight i space equals space 1 to straight n of space 3 to the power of 1 space plus space ih end exponent


equals space limit as straight h rightwards arrow 0 of space straight h space sum from straight i space equals space 1 to straight n of space 3 space times space 3 to the power of ih


equals space limit as straight h rightwards arrow 0 of space 3 straight h space sum from straight i space equals space 1 to straight n of space 3 to the power of ih


equals space limit as straight h rightwards arrow 0 of space 3 straight h space open square brackets 3 to the power of straight h space plus space 3 to the power of 2 straight h end exponent space plus space 3 to the power of 3 straight h end exponent space plus space........ space plus space 3 to the power of nh close square brackets


equals space limit as straight h rightwards arrow 0 of space open square brackets fraction numerator 3 straight h space times space 3 to the power of straight h space open parentheses 3 to the power of nh space minus space 1 close parentheses over denominator 3 to the power of straight h space minus space 1 end fraction close square brackets space space space space open parentheses because space straight S subscript straight n space equals space fraction numerator straight a open parentheses straight r to the power of straight n space minus space 1 close parentheses over denominator straight r space minus space 1 end fraction space semicolon space straight r space not equal to space 1 close parentheses


equals space limit as straight h rightwards arrow 0 of space open square brackets 3 space times space fraction numerator 1 over denominator begin display style fraction numerator 3 to the power of straight h space minus space 1 over denominator straight h end fraction end style end fraction space times space 3 to the power of straight h space open parentheses 3 to the power of 1 space minus space 1 close parentheses close square brackets space space space space open parentheses because space nh space equals space 1 close parentheses




              equals space 6 space times space fraction numerator 1 over denominator log subscript straight e space 3 end fraction space times space 3 to the power of 0 space


equals space fraction numerator 6 over denominator log subscript straight e space 3 end fraction space


equals bold space bold 6 bold space bold log subscript bold 3 bold space bold e



              


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નીચે આપેલાં નિયત સંકલિતને સરવાળાના લક્ષ સ્વરૂપે મેળવો :
integral from log subscript straight e space 2 to log subscript straight e space 5 of space straight e to the power of straight x space dx


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