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દ્વાવણો

1 કિગ્રા પાણીમાં 13.44 ગ્રામ CuCl₂ દ્વાવ્ય કરવાથી મળતા દ્વાવણ માટે $bold increment bold T subscript bold b$ શોધો. $bold K subscript bold b bold space bold equals bold space bold 0 bold. bold 52 bold space bold K$ કિગ્રા/મોલ $bold CuCl subscript bold 2$ નો અણુભાર = 134.4 ગ્રામ/મોલ.

0.04
0.2
0.32
0.16

0.16

bold increment bold T subscript bold b bold space bold equals bold space fraction numerator bold K subscript bold b bold space bold. bold space bold W bold space bold cross times bold space bold 1000 over denominator bold M bold space bold cross times bold space bold Wo end fraction bold space bold equals bold space fraction numerator bold 0 bold. bold 52 bold space bold cross times bold space bold 13 bold. bold 44 bold space bold cross times bold space bold 1000 over denominator bold 134 bold. bold 4 bold space bold cross times bold space bold 1000 end fraction

bold increment bold T subscript bold left parenthesis bold b bold right parenthesis end subscript

(જો પદાર્થ વિદ્યુત અવિભાજ્ય હોય તો) = 0.052 K પરંતુ

bold CuCl subscript bold 2 bold space bold rightwards arrow bold space bold Cu to the power of bold 2 bold plus end exponent bold space bold plus bold space bold 2 bold Cl to the power of bold minus

આયનો(કણો)ની સંખ્યા ત્રણ ગણી હોવાથી

bold increment bold T subscript bold b bold space bold equals bold space bold 0 bold. bold 052 bold space bold cross times bold space bold 3 bold space bold space bold space bold space bold space bold space bold space bold space bold space bold equals bold space bold 0 bold. bold 156 bold space bold space bold space bold space bold space bold space bold space bold space bold space bold equals bold space bold 0 bold. bold 16 bold space bold K bold space bold space bold space

bold increment bold T subscript bold b bold space bold equals bold space fraction numerator bold K subscript bold b bold space bold. bold space bold W bold space bold cross times bold space bold 1000 over denominator bold M bold space bold cross times bold space bold Wo end fraction bold space bold equals bold space fraction numerator bold 0 bold. bold 52 bold space bold cross times bold space bold 13 bold. bold 44 bold space bold cross times bold space bold 1000 over denominator bold 134 bold. bold 4 bold space bold cross times bold space bold 1000 end fraction

bold increment bold T subscript bold left parenthesis bold b bold right parenthesis end subscript

(જો પદાર્થ વિદ્યુત અવિભાજ્ય હોય તો) = 0.052 K પરંતુ

bold CuCl subscript bold 2 bold space bold rightwards arrow bold space bold Cu to the power of bold 2 bold plus end exponent bold space bold plus bold space bold 2 bold Cl to the power of bold minus

આયનો(કણો)ની સંખ્યા ત્રણ ગણી હોવાથી

bold increment bold T subscript bold b bold space bold equals bold space bold 0 bold. bold 052 bold space bold cross times bold space bold 3 bold space bold space bold space bold space bold space bold space bold space bold space bold space bold equals bold space bold 0 bold. bold 156 bold space bold space bold space bold space bold space bold space bold space bold space bold space bold equals bold space bold 0 bold. bold 16 bold space bold K bold space bold space bold space

જો કોઈ જલીય દ્વાવણનું ઠારબિંદુ -.186 $degree$ સેલ્સિયમ હોય તથા $bold K subscript bold f bold space bold equals bold space bold 1 bold. bold 86 bold degree bold space$ સે. કિગ્રા. મોલ^-1 અને $bold K subscript bold b bold space bold equals bold space bold 0 bold. bold 512 bold degree bold space$ સે. ક્રિગ્રા મોલ^-1 તો ઉત્કલનબિંદુમાં થતો વધારો કેટલો થાય ?