If a matrix A has 12 elements, what arc the possible orders it can have 7 What if it has 7 elements ?

Number of elements = 12
∴possible orders of the matrix are
1 x 12, 12 x 1,2 X 6. 6 x 2,3 x 4,4 x 3
If numbers of elements = 7, then possible orders are 1 x 7. 7 x 1

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Construct a 3 x 3 matrix w'hose elements are giv en by a,1, = 2 i – 3 j

Let A = [a i] be required 3 x3 matrix    
where a,ij , = 2 i – 3 j    
∴ a11, = 2–3 = –1. a12 = 2–6 = 4. a13,= 2–9 = 7
a21 = 4 — 3 = 1. a22 = 4 — 6 = —2 . a23  = 4 –9 = 5
a31 = 6 – 3 = 3, = 6 – 6 = 0 , a33 = 6 – 9 = –3

therefore space space space space space straight A equals open square brackets table row cell negative 1 end cell cell negative 4 end cell cell negative 7 end cell row 1 cell negative 2 end cell cell negative 5 end cell row 3 0 cell negative 3 end cell end table close square brackets

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Consider the following information regarding the number of men and women workers in three factories I. II and III

 

Men Workers

Women Workers

I

30

25

II

25

31

III

27

26

Represent the above information in the form of a 3 x 2 matrix. What does the entry in the third row and second column represent ?


The given information is

Factory

Men Workers

Women Worker:

I

, 30

25

II

' 25

31

III

27

26

The information is represented in the form of a 3 X 2 matrix as follows :

straight A equals open square brackets table row 30 25 row 25 31 row 27 26 end table close square brackets

The entry in the third row and second column represents the number of women workers in factory III.

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If a matrix has 8 elements, what arc the possible orders it can have ?

 

We know' that if a matrix is of order m x n, it has mn elements. Therefore, for finding all possible orders of a matrix with 8 elements, we will find all ordered pairs of natural numbers, whose product is 8.

∴ all possible ordered pairs are (1.8), (8, I), (4, 2). (2, 4)
∴ possible orders are I x 8, 8 x 1, 2 x 4, 4 x 2.

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Construct a 3 x 4 matrix whose elements are
ai  j = i +J  

Let A = [ aii] be required 3 x 4 matrix where aij= i + j
therefore space space spacea11 = 1 + 1 = 2, a12 =1+2, a13=1 + 3 = 4, a14 = 1 + 4 = 5
      a21 = 1 + 1 = 2, a22 =1+2, a23=1 + 3 = 4, a24 = 1 + 4 = 6
      a31 = 1 + 1 = 2, a32 =1+2, a33=1 + 3 = 4, a34 = 1 + 4 = 7 

therefore space space space space straight A equals open square brackets table row 2 3 4 5 row 3 4 5 6 row 4 5 6 7 end table close square brackets   
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