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Electric Charges and Fields

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Dipole in a Uniform External Field

A uniform electric field has constant magnitude and fixed direction. Such a field is produced between the plates of a charged parallel plate capacitor.

When two charges in a dipole are separated by some distance, the forces acting at different points result in a torque on the dipole.The torque tries to align the dipole with an electric field. Once aligned, the torque becomes 0.

Magnitude of torque

τ = qE x 2a sinθ
τ = 2qaE sinθ
τ = pEsinθ.

The vector form of torque is the cross product of dipole moment and electric field.

 

Physical significance of dipoles

  1. In most molecules, the centres of positive charges and of negative charges lie at the same place. Therefore, their dipole moment is zero. For example CO2 and CH4. However, they develop a dipole moment when an electric field is applied. 
  2. In some molecules, the centres of negative charges and of positive charges do not coincide. Therefore they have a permanent electric dipole moment, even in the absence of an electric field. Such molecules are called polar molecules. For example H2O.

The field of an electric dipole

The magnitudes of the electric field due to the two charges +q and -q are given by,

straight E subscript plus straight q end subscript space equals space fraction numerator straight q over denominator 4 space πε subscript 0 end fraction fraction numerator 1 over denominator straight r squared space plus straight a squared end fraction space..... space left parenthesis straight i right parenthesis
straight E subscript negative straight q end subscript space equals space fraction numerator straight q over denominator 4 πε subscript 0 end fraction fraction numerator 1 over denominator straight r squared plus straight a squared end fraction space space....... space left parenthesis ii right parenthesis

The directions of E+q and E-q are as shown in the figure. The components normal to the dipole axis cancel away. The components along the dipole axis add up.
Therefore, Total electric field.

E = - (E+q + E-q) cosθ p [Negative sign shows that field is opposite to p]

straight E space equals space minus fraction numerator 2 qa over denominator 4 πε subscript 0 space left parenthesis straight r squared space plus straight a squared right parenthesis to the power of begin display style 3 over 2 end style end exponent end fraction space space space... left parenthesis iiii right parenthesis

At large distances (r>>a),this reduces to

straight E space equals negative fraction numerator 2 qa over denominator 4 πε subscript 0 straight r cubed end fraction straight p with hat on top space space.... left parenthesis iv right parenthesis
because space straight p with rightwards arrow on top space equals space straight q space straight x space 2 straight a straight p with hat on top
therefore space straight E space equals space fraction numerator negative straight p with rightwards arrow on top over denominator 4 πε subscript 0 straight r cubed end fraction space left parenthesis straight r greater than greater than straight a right parenthesis

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