Book Store

Download books and chapters from book store.
Currently only available for.
CBSE

Previous Year Papers

Download the PDF Question Papers Free for off line practice and view the Solutions online.
Currently only available for.
Class 10 Class 12
Advertisement

Force And Laws Of Motion

Quickly browse through questions and notes on related topics. You can also download and read this topic offline.


Advertisement

Conservation of Momentum

When two (or more) bodies act upon one another, their total momentum remains constant (or conserved) provided no external forces are acting.

Initial momentum = Final momentum

Suppose, two objects A and B each of mass m1 and mass m2 are moving initially with velocities u1 and u2, strike each other after time t and start moving with velocities v1 and v2 respectively.

Now,

Initial momentum of object A = m1u1

Initial momentum of object B = m2u2

Final momentum of object A = m1v1

Final momentum of object B = m2v2

So, Rate of change of momentum in A,

straight F subscript 1 space equals space fraction numerator straight m subscript 1 straight v subscript 1 space minus straight m subscript 1 straight u subscript 1 over denominator straight t end fraction
space equals space fraction numerator straight m subscript 1 space left parenthesis straight v subscript 1 space minus straight u subscript 1 right parenthesis over denominator straight t end fraction space..... space left parenthesis straight i right parenthesis

And Rate of change of momentum in B,

straight F subscript 2 space equals space fraction numerator straight m subscript 2 straight v subscript 2 space minus straight m subscript 2 straight u subscript 2 over denominator straight t end fraction
space equals space fraction numerator straight m subscript 2 space left parenthesis straight v subscript 2 space minus straight u subscript 2 right parenthesis over denominator straight t end fraction space...... space left parenthesis ii right parenthesis
According space to space 3 rd space law space of space motion comma
straight F subscript 1 space equals space minus space straight F subscript 2
so comma space fraction numerator straight m subscript 1 space left parenthesis straight v subscript 1 minus straight u subscript 1 right parenthesis over denominator straight t end fraction space equals space fraction numerator straight m subscript 2 space left parenthesis straight v subscript 2 space minus straight u subscript 2 right parenthesis over denominator straight t end fraction

[From equations (i) & (ii)]

m1v1 – m2v2 = − m2v2 + m2u2

So, m1u1 + m2u2 = m1v1 + m2v2

Thus, Initial momentum = Final momentum

Advertisement