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 Multiple Choice QuestionsMultiple Choice Questions

1.

2-chloro-2-methylpentane on reaction with sodium methoxide in methanol yields:

  • Both a and c

  • Only c

  • Both a and b

  • All of these


D.

All of these

Strong nucleophile left parenthesis straight O with minus on top Me right parenthesis polar solvent (MeOH) gives elimination products Products over substitution products but all products are possible in different yields.

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2.

In the following sequence of reaction,
Toluene space rightwards arrow with KMnO subscript 4 on top space straight A space rightwards arrow with SOCl subscript 2 on top straight B space rightwards arrow from BaSO subscript 4 to straight H subscript 2 divided by Pd of straight C
The Product C is

  • C6H5COOH

  • C6H5CH3

  • C6H5CH2OH

  • C6H5CHO


D.

C6H5CHO

Toluene undergoes oxidation with KMnO4, forms benzoic acid. In this conversation, alkyl part of toluene converts into the carboxylic group. Further, the benzoic acid reacts with thionyl chloride (SOCl2) to give benzoyl chloride which upon reduction wth H2/Pd or BaSO4 forms benzaldehyde (Rosenmund reduction).
The reactions are


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3.

In the reaction,

CH subscript 3 COOH space rightwards arrow with LiAlH subscript 4 on top straight A space rightwards arrow with PCl subscript 3 on top straight B space rightwards arrow with Alc. KOH on top space straight C
The product C is

  • acetaldehyde

  • acetylene

  • ethylene

  • acetyl chloride


C.

ethylene

CH subscript 3 COOH space rightwards arrow with LiAlH subscript 4 on top space stack CH subscript 3 CH subscript 2 OH space with straight A below rightwards arrow with PCl subscript 5 on top space stack HC subscript 3 CH subscript 2 straight C with straight B below straight l space rightwards arrow from negative HCl to Alc space KOH of space stack CH subscript 2 equals CH subscript 2 with straight C below
LiAlH4 causes reduction
PCl5 causes chlorination
Alc. KOH causes elimination reaction
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4.

Which compound would give 5-keto-2-methyl hexanal upon ozonolysis?


B.

rightwards arrow from increment comma space space Zn comma space straight H subscript 2 straight O subscript 2 to straight O subscript 3 space space space space space of
space space space space space space space space space space space space space straight O space space space space space space space space space space space space space space space space space space space space space space space space space space space CH subscript 3
stack CH subscript 3 with 1 below minus space stack straight C with 5 below with vertical line vertical line on top minus straight C with 4 below straight H subscript 2 minus straight C with 3 below straight H subscript 2 minus stack straight C with vertical line on top with 2 below straight H minus CHO with 1 below
5-Keto-2-methyl hexanal
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5.

Compound (A), C8H9Br, gives a white precipitate when warmed with alcoholic AgNO3. Oxidation of (A) gives a acid (B), C8H6O4. (B) easily forms anhydride on heating. Identify the compound (A)


D.

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6.

Write IUPAC name of following compound

       

  • 2-amino-4-hydroxybenzoic acid

  • 6-amino-4-hydroxybenzoic acid

  • 3-amino-4-carboxyphenol

  • 2-carboxy-4-hydroxyaniline


A.

2-amino-4-hydroxybenzoic acid

                 

Priority order of functional groups is

                -COOH > -OH> -NH,

Therefore, IUPAC name of the compound is as follows

                             


7.

Sodium phenoxide when heated with CO2 under pressure at 125oC yields a product which on acetylation products C.


A.

It is a Kolbe Schmidt reaction.

The second step of the reaction is an example of acetylation reaction.

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8.

The strongest acid amongst the following compounds is

  • CH3COOH

  • HCOOH

  • CH3CH2CH(Cl)CO2H

  • ClCH2CH2CH2COOH


C.

CH3CH2CH(Cl)CO2H

α-chlorobutyric acid is more stronger acid than others due to - I effect of Cl. 

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9.

Trichloroacetaldehyde was subjected to Cannizzaro's reaction by using NaOH. The mixture of the products contains sodium trichloroacetate ion and another compound. The other compound is

  • 2, 2, 2-Trichloroethanol

  • Trichloromethanol

  • 2, 2, 2-Trichloropropanol

  • Chloroform


A.

2, 2, 2-Trichloroethanol

The Cannizzaro product of given reaction yields 2, 2, 2-trichloroethanol.

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10.

The most suitable reagent for the conversion of 

R-CH2 -OH →R- CHO is

  • KMnO4

  • K2Cr2O7

  • CrO3

  • PCC (pyridinium chlorochromate)


D.

PCC (pyridinium chlorochromate)

straight R space minus space CH subscript 2 OH space rightwards arrow with PCC on top space straight R space minus space CH equals straight O
Pyridinium chlorochromate is the mild oxidising agent which causes conversion of alcohol to aldehyde stage, While others cause conversion of alcohol to acid.
367 Views