Short Answer TypeGive reasons for the following:
(i) (CH3)3P = O exists but (CH3)3N = O does not.
(ii) Oxygen has less electron gain enthalpy with the negative sign than sulphur.
(iii) H3PO2 is a stronger reducing agent than H3PO3.
Give reasons:
Fluoride ion has higher hydration enthalpy than chloride ion.
The size of fluoride ion is small as compared to the chloride ion. Hence, when the two are dissolved in water, the energy of hydration released in the case of fluoride ion will be more than chloride ion due to stronger interactions (ion-dipole) between the ion and the water molecules.
How is the variability in oxidation states of transition metals different from that of the p-block elements?
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