Consider the special case of Identity (IV) with b = –a. What do you get? It is related to Identity (III).
Use a suitable identity to get each of the following products.
(1.1m - 0.41) (1.1m + 0.4)
Use a suitable identity to get each of the following products.
(-a + c) (-a + c)
Using the identity, (a + b)2 = a2 + 2ab + c2 , we have
(-a + c) (-a + c) = (-a + c)2
= (-a)2 + 2(-a)(c) + (c)2
= a2 + 2 (-ac) + c2
= a2 - 2ac + c2