Use differentials to approximate: from Mathematics Application

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 Multiple Choice QuestionsShort Answer Type

361.

Use differentials to approximate:
square root of 3.968 end root




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362.

Use differentials to approximate:
square root of 25.2 end root





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363.

Use differentials to approximate:
left parenthesis 0.0037 right parenthesis to the power of 1 half end exponent







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364.

Use differentials to approximate:
square root of 36.3 end root








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365.

Use differentials to approximate:
square root of 49.7 end root








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366.

Use differentials to approximate:
square root of 401









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367.

Use differentials to approximate:
square root of 402










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368.

Use differentials to approximate:
square root of 51












 Take space space space straight y space equals space square root of straight x comma space space space space space space straight x space equals space 49 comma space space space space dx space equals space δx space equals space 2 space space space so space that space straight x space plus space δx space equals space 51

  Now comma space straight y plus δy space equals space square root of straight x plus δx end root space space space space space space space rightwards double arrow space space space space space δy space equals space square root of straight x plus δx end root space minus space straight y space equals space square root of 51 space minus space 7
space rightwards double arrow space space space space space space square root of 51 space equals space δy space plus space 7 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space... left parenthesis 1 right parenthesis space space space space space space space


Now   δy is approximately equal to dy 

 and space space space space space space dy space equals space dy over dx dx space equals space fraction numerator 1 over denominator 2 square root of straight x end fraction dx space equals space fraction numerator 1 over denominator 2 left parenthesis 7 right parenthesis end fraction left parenthesis 2 right parenthesis space equals space 1 over 7 space equals space 0.14
therefore space space space from space left parenthesis 1 right parenthesis comma space space space space square root of 51 space equals space 0.14 plus 7 space equals 7.14.



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369.

Use differentials to approximate:
square root of 26












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370. Use differentials to approximate the cube root of 28.
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