If PQ is a double ordinate of the hyperbola x2a2 - 

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 Multiple Choice QuestionsMultiple Choice Questions

251.

A line passing through the point of intersection of x + y = 4 and x - y = 2 makes an angle tan-134 with the x-axis. It intersects the parabola y2 = 4(x-3) at points x1 , y1 and x2, y2 respectively. Then, x1 - x2

  • 169

  • 329

  • 409

  • 809


252.

The equation of auxiliary circle of the ellipse 16x2 + 25y2 + 32x - 100y = 284 is

  • x2 + y2 + 2x - 4y - 20 = 0

  • x2 + y2 + 2x - 4y = 0

  • (x + 1)2 + (y - 2)2 = 400

  • (x + 1)2 + (y - 2)2 = 225


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253.

If PQ is a double ordinate of the hyperbola x2a2 - y2b2 = 1 such that OPQ is equilateral. O being the centre. Then, the eccentricity e satisfies 

  • 1 < e < 23

  • e = 22

  • e = 32

  • e > 23


D.

e > 23

Given equation of hyperbola is x2a2 - y2b2 = 1 and OPQ is an equilateral triangle. PQ is double ordinate of the hyperbola.

Let the coordinates of P and Q be (asecθ, btanθ) and (asecθ, - btanθ), respectively.

In OPQ,OP = PQ a2sec2θ + b2tan2θ 2btanθ2 a2sec2θ = 3b2tan2θ sin2θ = a23b2

Now, sin2θ < 1

 a23b2 < 1 b2a2 > 13 1 + b2a2 > 43 e2 > 43 e > 23


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254.

If the vertex of the conic y - 4y = 4x - 4a always lies between the straight lines x + y = 3 and 2x + 2y - 1 = 0, then

  • 2 < a < 4

  • - 12 < a < 2

  • 0 < a < 2

  • - 12 < a < 32


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255.

The locus of the mid-points of chords of the circle x2 + y2 = 1, which subtends a right angle at the origin, is

  • x2 + y214

  • x2 + y2 = 12

  • xy = 0

  • x2 - y2 = 0


256.
  • x = - a

  • x = a

  • x = 0

  • x = - a2


257.

The points of the ellipse 16x2 + 9y2 = 400 at which the ordinate decreases at the same rate at which the abscissa increases is/are given by

  • 3, 163 and - 3, - 163

  • 3, - 163 and - 3, 163

  • 116, 19 and - 116, - 19

  • 116, - 19 and - 116, 19


258.

If the parabola x2 = ay makes an intercept of length 40 units on the line y - 2x = 1, then a is equal to

  • 1

  • - 2

  • - 1

  • 2


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259.

If the vertex of the conic y - 4y = 4x - 4a always lies between the straight lines x + y = 3 and 2x + 2y - 1 = 0, then

  • 2 < a < 4

  • - 12 < a < 2

  • 0 < a < 2

  • - 12 < a < 32


260.

Number of intersecting points of the conics 4x2 + 9y2 = 1 and 4x2 + y2 = 4 is

  • 1

  • 2

  • 3

  • 0


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