The point on the straight line y = 2x + 11 which is nearest to th

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 Multiple Choice QuestionsMultiple Choice Questions

441.

A conic section represents a circle, if its eccentricity e is

  • e < 0

  • e > 0

  • e = 0

  • None of these


442.

The equation of circle passing through the points (0, 2) (3, 3) and having its centre on the x-axis is

  • x2 + y2 - 14x - 12 = 0

  • 3x2 + 3y2 - 22x - 4 = 0

  • 3x2 + 3y2 - 14x - 12 = 0

  • None of the above


443.

The equation of a circle passing through origin and radius is a, is

  • (x - a)2 + (y - a)2 = a2

  • x2 + y2 = a2

  • (x - a)2 + y2 = a2

  • None of the above


444.

Equation of tangent to the circle x2 + y2 - 2x - 2y + 1 = 0 perpendicular to y = x is given by

  • x + y ± 1 = 0

  • x + y = 2 ± 3

  • x + y ± 3 = 0

  • None of these


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445.

The locus of centre of circles which cuts orthogonally the circle x2 + y2 - 4x + 8 = 0 and touches x + 1 = 0, is

  • y2 + 6x + 7 = 0

  • x2 + y2 + 2x + 3 = 0

  • x2 + 3y + 4 = 0

  • None of the above


446.

The condition for the line lx + my + n = 0 to be a normal to x225 + y29 = 1 is

  • l29 + m2l25 = n2256

  • 9m2 + 25l2 = 256n2

  • l29 - m2l25 = n2256

  • None of these


447.

The radical centre of the system of circles

            x2 + y2 + 4x + 7 = 0,

2(x2 + y2) + 3x + 5y + 9 = 0

and               x2 + y2 + y = 0 is

  • (- 2, - 1)

  • (1, - 2)

  • (- 1, - 2)

  • None of these


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448.

The point on the straight line y = 2x + 11 which is nearest to the circle 16(x2 + y) + 32x - 8y - 50 = 0, is

  • 92, 2

  • 92, - 2

  • - 92, 2

  • - 92, - 2


C.

- 92, 2

Let required point be α, β on the straight line y = 2x + 11, whch is nearest to the circle

16x2 + y2 + 32x - 8y - 50 = 0 x2 + y2 + 2x - 12y - 5016 = 0 Centre of circle = - 1, 14and radius = 1 + 116 + 5016 = 674Now, equation of straight line passing throughcentre - 1, - 14 and α, β is   y - 14 = β - 14α + 1x + 1     ...i

Now, gradient of this straight line = β - 14α + 1Sine, straightline (i) is perpendicular to the liney = 2x + 11 β - 14α + 1 × 2 = - 1    m1m2 = - 1  2β - 12 = - α - 1   2β + α = - 1 + 12 = - 12 4β + 2α = - 1             ...ii

 Point (α, β) lies on straight line     y = 2x + 11 β = 2α + 11 β - 2α = 11      ...iiiOn solving Eqs (i) and (ii), we get       5β = 10  β = 2and  2α = 2 - 11 = - 9     α = - 92 Required point is - 92, 2.

 


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449.

The locus of the extrimities of the latusrectum of the family of ellipses b2x2 + y2 = a2b2 having a given major axis, is

  • x2 ± ay = a2

  • y2 ± bx = a2

  • x2 ± by = a2

  • y2 ± ax = b2


450.

The number of common tangents to two circles x2 + y2 = 4 and x2 + y2 - 8x + 12 = 0 is

  • 1

  • 2

  • 3

  • 4


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