If the line 2x + 5y = 12 intersects the ellipse 4x2 + 5y2 =

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 Multiple Choice QuestionsMultiple Choice Questions

541.

If a chord of the parabola y = 4x passes through its focus and makes an angle 0 with the X-axis, then its length is

  • 4cos2θ

  • 4sin2θ

  • 4csc2θ

  • 4sec2θ


542.

If the straight line y = mx + c is parallel to the axis of the parabola y = bx and intersects the parabola at c28, c, then the length of the latus rectum is

  • 2

  • 3

  • 4

  • 8


543.

The eccentricity of the ellipse x2 + 4y2 + 2x + 16y + 13 = 0 is

  • 32

  • 12

  • 13

  • 12


544.

The angle between the asymptotes of the hyperbola x2 - 3y2 = 3 is

  • π6

  • π4

  • π3

  • π2


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545.

If the area of the triangle formed by the pair of lines 8x- 6xy + y= 0 and the line 2x + 3y = a is 7, then a is equal to

  • 14

  • 142

  • 282

  • 28


546.

If the line x + 3y = 0 is the tangent at (0, 0) to the circle of radius 1, then the centre of one such circle is

  • (3, 0)

  • - 110, 310

  • 310, - 310

  • 110, 310


547.

A circle passes through the point (3, 4) and cuts the circle x+ y= aorthogonally; the locus of its centre is a straight line. If the distance of this straight line from the origin is 25, then a is equal to

  • 250

  • 225

  • 100

  • 25


548.

The equation to the line joining the centres of the circles belonging to the coaxial system of circles 4x+ 4y- 12x + 6y - 3 + λ(x + 2y - 6) = 0 is

  • 8x - 4y - 15 = 0

  • 8x - 4y + 15 = 0

  • 3x - 4y - 5 = 0

  • 3x - 4y + 5 = 0


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549.

Let x + y = k be a normal to the parabola y2 = 12x. If p is length of the perpendicular from the focus of the parabola onto this normal, then 4k - 2p2 is equal to

  • 1

  • 0

  • - 1

  • 2


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550.

If the line 2x + 5y = 12 intersects the ellipse 4x+ 5y2 = 20 in two distinct points A and B,then mid-point of AB is

  • (0, 1)

  • (1, 2)

  • (1, 0)

  • (2, 1)


C.

(1, 0)

Since, the line 2x +5y = 12 intersect the ellipse 4x2 + 5y2 = 20 412 - 5y22 + 5y2 = 20 144 + 25y2 - 120y + 5y2 = 20 30y2 - 120y + 5y2 = 20 15y2 - 60y + 62 = 0 y = 60 ± 602 - 4 × 15 × 62215         = 60 ± 3600 - 372030 = 60 ± - 12030Hence, no real value of y existHence, no intersection is possible


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