Find a one parameter family of solutions of each of the followin

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsLong Answer Type

261.

Find one-parameter families of solution curves of the following differential equation:
left parenthesis 1 plus straight x squared right parenthesis space dy space plus space 2 xy space dx space equals space cot space straight x space dx space space space space left parenthesis straight x not equal to 0 right parenthesis
  

75 Views

262.

Find one-parameter families of solution curves of the following differential equation:
           straight x dy over dx plus straight y minus straight x plus straight x space straight y space cot space straight x space equals space 0 space space space left parenthesis straight x not equal to 0 right parenthesis

  

74 Views

263.

Solve:  open parentheses fraction numerator straight e to the power of negative 2 square root of straight x end exponent over denominator square root of straight x end fraction minus fraction numerator straight y over denominator square root of straight x end fraction close parentheses dx over dy equals 1 comma space space space straight x not equal to space 0.

75 Views

264. Solve the following differential equation:
dy over dx space plus 2 space straight y space tan space straight x space equals space sin space straight x
79 Views

Advertisement
265. For the differential equation, find the general solution:
dy over dx plus 2 straight y space equals sin space straight x
74 Views

266. Solve the following differential equation:
sin space straight x space dy over dx plus straight y space cosx space equals space cos space straight x space sin squared straight x

73 Views

 Multiple Choice QuestionsShort Answer Type

267. Find a one parameter family of solutions of each of the following differential equation:
straight y apostrophe cos squared straight x space equals space tanx minus space straight y
74 Views

Advertisement

268. Find a one parameter family of solutions of each of the following differential equation:
                             dy over dx equals negative fraction numerator straight x plus straight y space cosx over denominator 1 plus sinx end fraction


The given differential equation is
                            dy over dx equals negative fraction numerator straight x plus straight y space cosx over denominator 1 plus sinx end fraction space space space space space or space space space dy over dx space equals negative fraction numerator straight x over denominator 1 plus sinx end fraction minus straight y fraction numerator cosx over denominator 1 plus sinx end fraction
or    dy over dx plus open parentheses fraction numerator cos space straight x over denominator 1 plus sinx end fraction close parentheses straight y space equals space minus fraction numerator straight x over denominator 1 plus sinx end fraction
Comparing it with dy over dx plus Py space equals space straight Q comma space we space get comma
                            straight P space equals space fraction numerator cosx over denominator 1 plus sinx end fraction comma space space space straight Q space equals negative fraction numerator straight x over denominator 1 plus sinx end fraction

                   integral straight P space dx space equals space integral fraction numerator cosx over denominator 1 plus sinx end fraction dx space equals space log space left parenthesis 1 plus sinx right parenthesis

therefore space space space space space space straight e to the power of integral straight P space dx end exponent space equals space straight e to the power of log space left parenthesis 1 plus space sinx right parenthesis end exponent space equals space log space left parenthesis 1 plus sin space straight x right parenthesis

therefore  solution of differential equation is
                         straight y space straight e to the power of integral Pdx space end exponent space equals space integral straight Q space straight e to the power of integral Pdx end exponent plus straight c
or        straight y left parenthesis 1 plus sin space straight x right parenthesis space equals space integral fraction numerator negative straight x over denominator 1 plus sinx end fraction left parenthesis 1 plus sinx right parenthesis space dx plus straight c

or        straight y space straight y left parenthesis 1 plus sinx right parenthesis space equals space minus integral straight x space dx plus straight c.
or         straight y left parenthesis 1 plus sinx right parenthesis space equals space minus straight x squared over 2 plus straight c.

76 Views

Advertisement
Advertisement

 Multiple Choice QuestionsLong Answer Type

269.

Solve:
straight y apostrophe minus 2 straight y space equals space cos space 3 straight x

71 Views

 Multiple Choice QuestionsShort Answer Type

270.

Solve:
straight y apostrophe plus straight y space equals space sin space straight x

85 Views

Advertisement