The solution of ∫2xdtt2 - 1 = π12

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 Multiple Choice QuestionsMultiple Choice Questions

491.

010x1010 - x10 + x10dx is equal to

  • 10

  • 5

  • 2

  • 12


492.

The value of 01xexdx is equal to

  • e - 22

  • 2(e - 2)

  • 2e - 1

  • 2(e - 1)


493.

1xlogxloglogxdx is equal to

  • loglogx + C

  • loglogxlogx + C

  • loglogloglogx + C

  • logloglogx + C


494.

3x1 - 9xdx is equal to

  • log3sin-13x + C

  • 13sin-13x + C

  • 13sin-13x +C

  • 19sin-13x +C


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495.

The value of the integral cosxsinx + cosxdx is equal to

  • x + logsinx + cosx + C

  • 12x + logsinx + cosx +C

  • logsinx + cosx + C

  • x2 + logsinx + cosx + C


496.

27e9x + e12x13dx is equal to

  • 1427 + e3x13 + C

  • 1427 + e3x23 + C

  • 1327 + e3x43 + C

  • 1427 + e3x43 + C

     


497.

4dxx24 - 9x2 is equal to

  • 4 - 9x2 + C

  • - 234 - 9x2 + C

  • - 4 - 9x2x + C

  • 234 - 9x2x + C


498.

e- xcscx1 + cotxdx is equal to

  • e- xcscx + C

  • - e- xcscx + C

  • e- xcscx + cotx + C

  • e- xcscx - tanx + C


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499.

sinx + cosxe- x + sinxdx is equal to

  • log1 - exsinx + C

  • log1 + exsinx + C

  • log1 + exsinx + C

  • log1 - e- xsinx + C


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500.

The solution of 2xdtt2 - 1 = π12 is

  • 1

  • 2

  • 3

  • 4


B.

2

Given,2xdtt2 - 1 = π12  sec-1t2x = π12 sec-1x - sec-12 = π12 sec-1x = π12 + π4 = 4π12 = π3             x = secπ3 = 2


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