∫01ddxsin-12x1 + x2dx is equal to : from Math

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 Multiple Choice QuestionsMultiple Choice Questions

541.

0xftdt = x2 + ex (x > 0), then f(1) is equal to

  • 1 + e

  • 2 + e

  • 3 + e

  • e


542.

x + 1x12dx =

  • - x3/2 + x1/2 + C

  • x1/2

  • x3/2 + 2x1/2 + C

  • 2x323 + 2x12 + C


543.

dxex + e- x + 2 is equal to

  • 1ex + 1 + C

  • - 1ex + 1 + C

  • 11 + e- x + C

  • 1e- x - 1 + C


544.

- 10dxx2 + x + 2 is equal to

  • π4

  • π2

  • π

  • 47tan-117


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545.

- 221 - x2dx is equal to :

  • 4

  • 2

  • - 2

  • 0


546.

tanxsinxcosxdx is equal to :

  • 2tanx + c

  • cotx + c

  • 2tanx + c

  • tan2x + c


547.

dxx2 + 4x + 13 is equal to :

  • logx2 + 4x + 130 + c

  • 13tan-1x + 23 + c

  • log2x + 4 + c

  • 1x2 + 4x + 13 + c


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548.

01ddxsin-12x1 + x2dx is equal to :

  • 0

  • π

  • π2

  • π4


C.

π2

Let I = 01ddxsin-12x1 + x2dxLet x = tanθ  I = dxsin-1sin2θdx        = 201ddxtan-11 - tan-10        = 2 . π4 = π2


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549.

0π2sinxsinx + cosxdx is equal to

  • π

  • π2

  • π3

  • π4


550.

sinxsinx - αdx is equal to

  • x - αcosα + sinαlogsinx - α + c

  • sinx - α + sinx + c

  • x - αcosα + logsinx - α + c

  • cosx - α + cosx + c


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