The integral ∫110x3dx is approximately evaluated by

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861.

The integral 110x3dx is approximately evaluated by Trapezoidal rule 110x3dx = 31 + 1032 + α + 73 for  n = 3, then the value of α is

  • 43

  • 42

  • 53

  • None of these


A.

43

Here, h = 10 - 13 = 3 and y = x3
i xi yi
0 1 1
1 4 64
2 7 343
3 10 1000

110x3dx = 31 + 1032 + α + 73             = 31 + 103 + 243 + 73             = 31 + 1032 + 43 + 73On comparing, we get         α = 43


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862.

Let f(x) = uxvxgtdt. Then, f'(x) is equal to

  • g[v(x)] - g[u(x)]

  • g'[v(x)] - g'[u(x)]

  • g[v(x)] v'(x) - g[u(x)] u'(x)

  • None of the above


863.

The value of 0πcosxdx is

  • 1

  • 2

  • 0

  • 3


864.

sinx + cosx1 + sin2xdx equals

  • logsinx + cosx

  • x

  • logsincosx

  • logx


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865.

Using trapezoidal rule and taking n = 4, the value of 02dx1 + x will be

  • 1.1167

  • 1.1176

  • 1.118

  • None of these


866.

dxxxn + 1 is equal to

  • 1nlogexnxn + 1 + C

  • - 1nlogexn + 1xn + C

  • 1nlogexnxn + 1 + C

  • None of the above


867.

Evaluate dxxx5 + 2

  • 110logx5 + 1x5 + 2 + C

  • 15logx5x5 + 2 + C

  • 110logx5x5 + 2 + C

  • 110logx5 + 1x5 + 2 + C


868.

23x5 - x + xdx is equal to

  • 14

  • 1

  • 32

  • 12


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869.

I = - 11x2 + sinx1 + x2dx

  • 0

  • 2 + π2

  • 2 - π2

  • π2 - 2


870.

A curve is drawn to pass through the points given by the following table.
x 1 1.5 2 2.5 3 3.5 4
y 2 2.4 2.7 2.8 3 2.6 2.1

Using Simpson's 1/3rd rule, estimate the area bounded by the curve, the x-axis and the lines x = 1, x = 4

  • 7.47 sq units

  • 7.76 sq units

  • 7.78 sq units

  • 7.82 sq units


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