If ∠ZB and ∠Q are acute angles such that sin B = sin Q, then

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#6 {main}</pre> find the value of sinA. cosB + cosA. sinB
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116. If ∠ZB and ∠Q are acute angles such that sin B = sin Q, then prove that ∠B = ∠Q.


Let us consider two right angle triangles right angled at C and R respectively.
sinB space equals space AC over AB
Now,
  
Let us consider two right angle triangles right angled at C and R res
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#6 {main}</pre>
   But sin space straight B space equals space sin space straight Q space left parenthesis given right parenthesis
∴        AC over AB equals PR over PQ

rightwards double arrow space space space space space space space space AC over PR equals AB over PQ

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#6 {main}</pre>        ...(i)
In ΔABC,
Using Pythagoras theorem, we have
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#6 {main}</pre>
In increment PQR comma
Using Pythagoras theorem, we have
                      QR space equals space square root of PQ squared minus PR squared end root
So,           BC over QR equals fraction numerator straight K square root of PQ squared minus PR squared end root over denominator square root of PQ squared minus PR squared end root end fraction equals straight K space space space... left parenthesis ii right parenthesis
Comparing (i) and (ii), we get
                 AC over PR equals AB over PQ equals BC over QR
So, by using SSS similar condition
∴          space space increment ACB space tilde space increment PRQ
                angle straight B space equals space angle straight Q.

   

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